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AURORKA [14]
3 years ago
7

Help me with this math question

Mathematics
1 answer:
katrin [286]3 years ago
7 0

Answer:

uhhhhhhhhhhh 4 answer

Step-by-step explanation:

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PLZ HELP WORTH A LOT OF POINTS AND I HAVE 10 MINUTES!!!!
Lina20 [59]

Answer:

The area after 9 years will be 1,234 km^2

Step-by-step explanation:

In this question, we are tasked with calculating what the area of a certain forest that decreases at a certain percentage would be after some years.

To answer this question, we shall be using an exponential approximation.

Now, to use this exponential approximation, we shall be needing a supporting exponential mathematical equation.

This can be written as;

A = I(1-r)^t

where A is the new area we are looking for

I is the initial area which is 1700 according to the question

r is the rate of decrease which is 3.5% = 3.5/100 = 0.035

t is time which is 9 years according to the question

We plug these values and have the following;

A = 1700(1-0.035)^9

A = 1700(0.965)^9

A = 1,233.66

This is 1,234 km^2 to the nearest square kilometer

5 0
3 years ago
A store sells 5 T-shirts for $48.05. What is the unit cost per T-shirt?
jolli1 [7]

Answer:

$9.61 per shirt

Step-by-step explanation:

You take the total cost of $48.05 and divide it by the number of t-shirts which is 5.

48.05/5 = 9.61

8 0
3 years ago
If quadrilateral LMNO is a square, find the missing measures. Round your answers to the nearest tenth, if necessary. LN=46. What
aleksley [76]

The values of OM, PN, ON and MN of the given square are;

OM = 46

PN = 23

ON = 32.5

MN = 32.5

<h3>Pythagorean theorem</h3>

We are given;

LN = 46

  • Now, LN is the diagonal of the square and as such to get the sides of the square, we will make use of pythagoras theorem to get;

LO² + ON² = 46²

Since LO = ON, then;

2LO² = 46²

LO² = 46²/2

LO = √1058

LO = 32.5

Thus;

LO = ON = MN = 32.5

For the diagonals;

LN = OM = 46

Also; LP = PN = 46/2 = 23

Read more about pythagoras theorem at;brainly.com/question/3317136

4 0
3 years ago
A circle is centered at $O$ and has an area of $48 \pi.$ Let $Q$ and $R$ be points on the circle, and let $P$ be the circumcente
nikklg [1K]

Answer:

Area of Triangle QRP = 3\sqrt{3}

Step-by-step explanation:

According to Question , We have a circle With Centre 'O' & Area 48\pi .

Area Of Circle = 48\pi

\pir^{2} = 48\pi

r = \sqrt{48}

Now We Have Two Points Given On Circle Q & R , P Is Circumcentre Of Triangle QRO .

Thus A Circle Can Also Be Formed with Centre P . ( See attachment For Diagram )

Now The Diameter of Circle With Centre P = Radius Of Circle with Centre O

so Radius Of Circle With Centre P(r_{2}) = \frac{\sqrt{48}}{2}

Now We Have To Find Area Of Equilateral Triangle .

A = \frac{\sqrt{3}}{4} r_{2} ^{2}

A= \frac{\sqrt{3} }{4} * \frac{\sqrt{48} }{2}*\frac{\sqrt{48} }{2}

The Area Of PQR is = 3\sqrt{3}

For Diagram , Please Find In Attachment

7 0
3 years ago
Neeeeeed help not sure please help asap
lyudmila [28]
The correct answer is c

(it is 3 times the sum of 6 + 5 not 3 times 6 like a is suggesting)
3 0
3 years ago
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