the points (-6,0)(-2,0)(1,0)(3,0) all exist in the graph which is only correct for the second graph to make your self even more sure
since the zeros are given and it ia a polynomial you can figure out the facrored form
which will yield
f(x)=(x+6)(x+2)(x-1)(x-3)
conducting a simple sign test
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there will be 4 critical values
-6 -2 1 3
before -6 the sign of f(x) -*-*-*-= +
after -6 and before -2 the sign of f(x) +*-*-*-=-
after -2 and before 1 the sign of f(x) +*+*-*-=+
after 1 and before 3 the sign of f(x) +*+*+*-=-
after 3 the sign of f(x) +*+*+*+=+
which only fits the upper right graph
The answer at least i think is a
