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3 years ago

Determine the most precise name for the quadrilateral,

Mathematics

1 answer:

Georgia [21]3 years ago

3 0

Answer:

Rhombus

Step-by-step explanation:

This isnt a rectangle because it doesnt have right angles. and the precise name would be a rhombus

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NEED HELP ASAP!!!!!!!

zloy xaker [14]

Answer:

the second one

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

(1 pt) In a study of red/green color blindness, 950 men and 2050 women are randomly selected and tested. Among the men, 89 have

Ivahew [28]

Answer: (0.066,0.116)

Step-by-step explanation:

The confidence interval for proportion is given by :-

$p_1-p_2\pm z_{\alpha/2}\sqrt{\dfrac{p_1(1-p_1)}{n_1}+\dfrac{p_2(1-p_2)}{n_2}}$

Given : The proportion of men have red/green color blindness = $p_1=\dfrac{89}{950}\approx0.094$

The proportion of women have red/green color blindness = $p_2=\dfrac{6}{2050}\approx0.003$

Significance level : $\alpha=1-0.99=0.01$

Critical value : $z_{\alpha/2}=z_{0.005}=\pm2.576$

Now, the 99% confidence interval for the difference between the color blindness rates of men and women will be:-

$(0.094-0.003)\pm (2.576)\sqrt{\dfrac{0.094(1-0.094)}{950}+\dfrac{0.003(1-0.003)}{2050}}\approx0.091\pm 0.025\\\\=(0.09-0.025,0.09+0.025)=(0.066,\ 0.116)$

Hence, the 99% confidence interval for the difference between the color blindness rates of men and women= (0.066,0.116)

4 0

4 years ago

Does the equation y = 5(2.3)* model exponential growth, exponential decay or neither?

maria [59]

Exponential growth because maths is good

3 0

3 years ago

Read 2 more answers

Find the unit rate. Round to the nearest hundredth, if necessary.

OverLord2011 [107]

Basically, the unit rate is 1.99/18 or 0.110.

If we round 1.99 to 2.00, we instead get 0.111~

8 0

3 years ago

Find the approximate perimeter of ABC plotted below.

maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}$

$AB = \sqrt{4 + 4}$

$AB = \sqrt{16}$

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}$

$BC = \sqrt{25 + 49}$

$BC = \sqrt{74}$

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

$AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}$

$AC = \sqrt{47 + 25}$

$AC = \sqrt{74}$

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0

3 years ago