Answer:
attempts are required to find a matching pair if the digital fingerprint is 64 bits long.
attempts are required to find a matching pair if the digital fingerprint is 128 bits long.
Step-by-step explanation:
Each bit has two options. So
How many attempts are required to find a matching pair if the digital fingerprint is 64 bits long?
So for each of the 64 bits, we have the following number of options.
2 - 2 - 2 - 2 -... - 2
So, in all, there are
options.
So, attempts are required to find a matching pair if the digital fingerprint is 64 bits long.
128 bits long?
Using the same logic as the first question.
So, attempts are required to find a matching pair if the digital fingerprint is 128 bits long.
Given:
The graph of an exponential function.
To find:
The exponential growth factor as x increases by 1 unit.
Solution:
From the given graph, it is clear that the exponential function passes through the points (1,1) and (3,9). So, the equation of the exponential must must be satisfy by these points.
The general exponential function is:
...(i)
Where, a is the initial value and b is the growth factor.
Putting 
in (i), we get
...(ii)
Putting 
in (i), we get
...(iii)
Divide (iii) by (ii).
b is the the growth factor and the value of b is 3.
Therefore, the exponential growth factor is 3 as x increases by 1 unit.
Answer:
x=-5
Step-by-step explanation:
hope i helped
This item can be solved by the probability theorem called Bayes' theorem which states that the probability of event A occurring given event B is equal to,
P(A/B) = P(A)P(B/A) / P(B)
where P(B/A) is the probability that the test will yield positive if the person has the disease. P(A) is the probability will be present in any particular person which is equal to 0.04.
P(B) is the probability of positive result irrespective of whether the disease is present of not is calculated below.
P(B) = (0.94)x (0.04) + (0.06)(0.96) = 0.0952
Now, solving for P(A/B)
P(A/B) = (0.94)(0.04) / 0.0952 = 0.039
Thus, the answer is approximately 4%.
