What is the resistance of a light bulb if a potential difference of 120 V will produce a current of 0. 5 A in the bulb? 0. 0042
1 answer:
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Answer:
a
b
The value is
Explanation:
From the question we are told that
The mass is
The spring constant is
The instantaneous speed is
The position consider is x = 0.750A meters from equilibrium point
Generally from the law of energy conservation we have that
The kinetic energy induced by the hammer = The energy stored in the spring
So
Here a is the amplitude of the subsequent oscillations
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Generally from the law of energy conservation we have that
The kinetic energy by the hammer = The energy stored in the spring at the point considered + The kinetic energy at the considered point
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