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fenix001 [56]
3 years ago
6

A bullet of 5 gm is fired from a pistol of 1.5 kg. If the recoil velocity of pistol is 1.5 m/s,

Physics
1 answer:
Andreyy893 years ago
6 0

Answer:

-450 m/s

Explanation:

Momentum is conserved.

p₀ = p

0 = (1.5 kg) (1.5 m/s) + (0.005 kg) v

v = -450 m/s

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In Paul Hewitt's book, he poses this question: "If the forces that act on a bullet and the recoiling gun from which it is fired
Sauron [17]
They have different accelerations because of their masses. According to Newton's Second Law, an objects acceleration is inversely proportional to its mass. Therefore the object with the larger mass, in this case the gun, will have a smaller acceleration. In the same way, the less massive object, being the bullet, will have a higher acceleration.

Hope this helps :)
4 0
3 years ago
How do you find input energy with only the efficiency and output energy given?
iris [78.8K]

Answer:

power output/transformer efficiency multiply by 100%

Explanation:

derrive the formula from efficiency=power output/power input multiply by 100%

8 0
3 years ago
If velocity is in m/s and time is in sec, what is the unit of acceleration?​
WINSTONCH [101]
The unit of acceleration would be m/s² :)
6 0
2 years ago
WHO CAN ANSWER BOTH 14 and 15 WITH UNITS ILL PUT U AS BRAINLEST!
saw5 [17]

Answer:

14. V=8

15. V=40

Explanation:

simplifying:

14. 4 32/8

V=8

15. 20 1000/50

V=40

4 0
3 years ago
A piece of bismuth with a mass of 4.06 g 4.06 g gains 423 J 423 J of heat. If the specific heat of bismuth is 0.123 J / ( g ° C
Sholpan [36]

Answer: 846°C

Explanation:

The quantity of Heat Energy (Q) required to heat bismuth depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that:

Q = 423 joules

Mass of bismuth = 4.06g

C = 0.123 J/(g°C)

Φ = ?

Then, Q = MCΦ

423 J = 4.06g x 0.123 J/(g°C) x Φ

423 J = 0.5J/°C x Φ

Φ = (423J/ 0.5g°C)

Φ = 846°C

Thus, the change in temperature of the sample is 846°C

4 0
3 years ago
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