Can someone get this? Ive been trying and cant get it
1 answer:
<u>Given</u><u> </u><u>:</u><u>-</u>
- The roots of the function are 5 and -3 .
<u>To</u><u> </u><u>Find</u><u> </u><u>:</u><u>-</u>
<u>Answer</u><u> </u><u>:</u><u>-</u>
The roots of the function are 5 and -3 . In general we can write the Quadratic function with roots π and ∆ as ,
f(x) = ( x - π )(x-∆)
So on using this we have ,
f(x) = ( x -5)( x -(-3))
f(x) = (x-5)(x+3)
f(x) = x(x-5)+3(x-5)
f(x) = x² -5x +3x -15
f(x) = x² -2x -15
<u>Hence </u><u>the</u><u> required</u><u> </u><u>answer</u><u> </u><u>is </u><u>x²</u><u> </u><u>-2x </u><u>-</u><u>1</u><u>5</u><u>.</u>
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Hello,
well done.
As x^3-7x²-9x+63=(x-3)(x+3)(x-7) we must have x>3 and x>-3 and x>7 thus x>7
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x^3-7x²-9x+63=x^3-9x+(-7x²+63)=x(x²-9)-7(x²-9)=(x²-9)(x-7)=(x+3)(x-3)(x-7)
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