All categories

3 years ago

A box contains one each of $1, $5, $10, $20, and $100 bills. you reach in and withdraw one bill. what is the expected value?

1 answer:

galina1969 [7]3 years ago

4 0

The expected value is simply the average of the values of all of the bills.

The expected value is the sum of the values of each bill times the probability that that bill is drawn. 

There are 5 bills, 1, 5, 10, 20, 100. 

The probability of drawing one of the bills out of a hat is 1 out of 5, or 1/5. 

The expected value then is: 

EV = (1/5) * $1 + (1/5) * $5 +(1/5) * $10 +(1/5) * $20 +(1/5) * $100 

Rewriting, you can see that in this problem, EV is just the average of the five bill values 
EV = (1/5) * ($1 + $5 + $10 + $20 + $100) 

EV = $27.20 

Hope this helps,

You might be interested in

The system of equations graphed below has how many solutions ?

amm1812

Their parallel so never

4 0

4 years ago

Read 2 more answers

R, S, Q and P are the midpoints of OC, CB, BA and OA respectively.

Stolb23 [73]

Answer:

See below.

Step-by-step explanation:

Draw segment OB.

In triangle OBC, points R and S are the midpoints of sides OC and BC, respectively. That makes RS parallel to OB.

In triangle OBA, points P and Q are the midpoints of sides OA and BA, respectively. That makes PQ parallel to OB.

Since segments RS and PQ are parallel to segment OB, then RS and PQ are parallel to each other.

3 0

3 years ago

Two window washers start at the heights shown. One is rising, the other is descending. How long does it take for the two window

kvasek [131]

Answer:

After 18.32 seconds washer men will be at the same height.

Step-by-step explanation:

Given question is incomplete; here is the complete question.

Two window washers start at the heights shown. (A: 21 ft high rising 8 in per second. The other is 50 feet high descending 11 inches per second) one is rising one is descending. How long does it take for the two window washers to reach the same height? Explain

Two window washers are moving in opposite directions.

First window washer is at 21 ft and rising with the speed of 8 inches per second.

Second window washer is at 50 feet and descending with the speed of 11 inches per second.

Since 1 feet = 12 inches

Therefore, 21 feet = 21×12 = 252 inches

Similarly, 50 feet = 50 × 12 = 600 inches

Let both the window washer takes 't' time to be at the same height.

Height of the first window washer after t seconds = (252 + 8t) feet

Height of the second window washer after t seconds = (600 - 11t) feet

Since both are at the same height after time 't',

(252 + 8t) = (600 - 11t)

8t + 11t = 600 - 252

19t = 348

t = 18.32 seconds

Therefore, after 18.32 seconds washer men will be at the same height.

8 0

3 years ago

105.6 L/h = ___ L/min?

borishaifa [10]

Answer:

(105.6 L / hour) x (hour / 60 min) = (105.6 / 60) = 1.76L / min .

6 0

4 years ago

Read 2 more answers

2(a³+b²+11)+1(3+a³+b+11)

Ann [662]

Answer:

$2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36$

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

$2(a^3+b^2+11)+1(3+a^3+b+11)$

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

$2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14$

Therefore, $2(a^3+b^2+11)+1(3+a^3+b+11)$ is equal to:

$2a^3+2b^2+22+a^3+b+14$

Now, combining like terms using the commutative property of addition, we get:

$=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36$

Therefore, the simplified form is $3a^3+2b^2+b+36$

8 0

4 years ago