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morpeh [17]
3 years ago
12

A box contains one each of $1, $5, $10, $20, and $100 bills. you reach in and withdraw one bill. what is the expected value?

Mathematics
1 answer:
galina1969 [7]3 years ago
4 0
The expected value is simply the average of the values of all of the bills. 

<span>The expected value is the sum of the values of each bill times the probability that that bill is drawn. </span>

<span>There are 5 bills, 1, 5, 10, 20, 100. </span>

<span>The probability of drawing one of the bills out of a hat is 1 out of 5, or 1/5. </span>

<span>The expected value then is: </span>

<span>EV = (1/5) * $1 + (1/5) * $5 +(1/5) * $10 +(1/5) * $20 +(1/5) * $100 </span>

<span>Rewriting, you can see that in this problem, EV is just the average of the five bill values </span>
<span>EV = (1/5) * ($1 + $5 + $10 + $20 + $100) </span>

<span>EV = $27.20 </span>

<span>Hope this helps, </span>
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2 years ago
Twice the sum of a number and 5 equals 9 as a equation
ziro4ka [17]
Hello!

I believe it looks like this..

2*x+5=9

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3 years ago
Will give brainlst <br> Have a nice day
Zarrin [17]

Answer:

ok where are you from which country

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2 years ago
If the points at (-4, 3) and (2, 3) are reflected over the x-axis to create two new points, what shape can be formed by the four
Svetllana [295]

Answer:

Step-by-step explanation:

Let (a,b)\in \mathbb{R}^{2}, a reflection over the x-axis consists in the following operation:

(a,b) \rightarrow (a,-b)

If we know that X = (-4,3) and Y = (2, 3), then the points translated over the x-axis are X' = (-4, -3) and Y' = (2,-3), respectively. The most precise description of the shape is a rectangle for the following facts:

1) XX' = YY' = 8 and XY = X'Y' = 6.

2) X and X' have the same x-component.

3) Y and Y' have the same x-component.

4) X and Y have the same y-component.

5) X' and Y' have the same y-component.

A representation of the shape is included below as attachment.

3 0
2 years ago
What is the formula for midpoint??
Feliz [49]
(-4,4) (3,-2)
formula for finding mid point is
M=(x1+x2/2,y1+y2/2)
m=-4+3/2,4-2/2
m=(-1/2,1)
4 0
2 years ago
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