A box contains one each of $1, $5, $10, $20, and $100 bills. you reach in and withdraw one bill. what is the expected value?
1 answer:
The expected value is simply the average of the values of all of the bills. <span>The expected value is the sum of the values of each bill times the probability that that bill is drawn. </span> <span>There are 5 bills, 1, 5, 10, 20, 100. </span> <span>The probability of drawing one of the bills out of a hat is 1 out of 5, or 1/5. </span> <span>The expected value then is: </span> <span>EV = (1/5) * $1 + (1/5) * $5 +(1/5) * $10 +(1/5) * $20 +(1/5) * $100 </span> <span>Rewriting, you can see that in this problem, EV is just the average of the five bill values </span> <span>EV = (1/5) * ($1 + $5 + $10 + $20 + $100) </span> <span>EV = $27.20 </span> <span>Hope this helps, </span>
You might be interested in
Answer:
Step-by-step explanation:
In school i did these but i have no clue how to do them.I will try though:)
The answer is B since 6 times 12 is 72.
Place value of 4 is 4/100
Answer:
132
Step-by-step explanation:
48
+ 84
--------
132
_____