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Nataly_w [17]
3 years ago
6

In the coordinate plane, the point X (3, 1) is translated to the point X'(4, -1). Under the same translation, the points Y(-1, -

3) and Z (6, -2) are
translated to Y' and Z', respectively. What are the coordinates of Y' and Z?
Mathematics
1 answer:
torisob [31]3 years ago
7 0
<h3>Answer:y and z</h3>

Step-by-step explanation:

<h2>bc y and z is in the alphabet </h2>
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5 0
3 years ago
Please help with this 10 pts
Sever21 [200]
I think it is a direct variation because if you divide 9/3, 27/3, 39/13, and 60/20 it will all give you the same number which is 3.
I hope this helps.
6 0
3 years ago
W+3 3/8 =1 5/6=<br> I know the answer but i want to see if you get it
nasty-shy [4]

Answer:

...

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
1. Miles and Simon do chores to earn an allowance from their parents. Miles has $120 saved and gets a $10 allowance per week. Hi
Ket [755]

Answer:

If w represented the number of weeks he does his chores, the equations would be:

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Simon:75+15w

7 0
3 years ago
ln(y+1)-lny=1+3lnx . Express y in terms of x, in a form not involving logarithms. (4 marks, Maths CIE A level)
Delicious77 [7]
remember
ln(x)=log_e(x)
and
log_x(a)-log_x(b)= log_x( \frac{a}{b} )
and
log_a(b)=c means a^c=b
and
blog(a)=log(a^b)



so

ln(y+1)-ln(y)=1+3ln(x)
ln( \frac{y+1}{y} )=1+ln(x^3)

minus ln(x^3) from both sides

ln( \frac{y+1}{y}-ln(x^3) )=1
ln( \frac{y+1}{yx^3})=1
log_e( \frac{y+1}{yx^3})=1

translate

e^1=\frac{y+1}{yx^3}
e=\frac{y+1}{yx^3}

times both sides by yx^3

eyx^3=y+1

minus y from both sides

eyx^3-y=1
y(ex^3-1)=1

divide both sides by (ex³-1)

y= \frac{1}{ex^3-1}
6 0
3 years ago
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