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galina1969 [7]
3 years ago
9

Table The table shows the number of carnival tickets purchased and the corresponding number of entries in the raffle drawing. If

x is the number of tickets purchased and y is the number of entries in the raffle drawing, then the equation represents the table. How many entries would be in the raffle drawing if 20 tickets were purchased?

Mathematics
2 answers:
sattari [20]3 years ago
7 0

Answer:

b for the first one, d for the second one

Step-by-step explanation:

mojhsa [17]3 years ago
4 0

Answer:

Step-by-step explanation:

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Which is equivalent to 64 Superscript one-fourth?
Schach [20]

Answer:

2 RootIndex 4 StartRoot 4 EndRoot

Step-by-step explanation:

we have

64^{\frac{1}{4}}

Decompose the number 64 in prime factors

64=2^{6}=2^{4}2^{2}

substitute

64^{\frac{1}{4}}=(2^{4}2^{2})^{\frac{1}{4}}=2^{\frac{4}{4}}2^{\frac{2}{4}}=2\sqrt[4]{4}

7 0
3 years ago
Read 2 more answers
Find the domain of the rational expression: x-4/2x-6
marin [14]

Answer:

All real numbers except 3

Step-by-step explanation:

Given

\frac{x - 4}{2x - 6}

Required

Determine the domain

We start by writing the following inequality

2x - 6 \neq  0

Add 6 to both sides

2x -6 + 6 \neq = 0 + 6

2x \neq  6

Divide both sides by 2

\frac{2x}{2}\neq  \frac{6}{2}

x \neq  \frac{6}{2}

x \neq = 3

<em>As such, the domain of x is all real numbers except 3</em>

4 0
3 years ago
If f(n)= n²-n, then f(-4) is<br> O-20<br> 12<br> -12<br> 20
Harman [31]

Answer:

20

Step-by-step explanation:

Plug in -4 for n:

(-4)^2 - (-4) = 16 + 4 = 20

3 0
2 years ago
Find the area of the shaded region. Round your answer to the nearest hundredth.
Anit [1.1K]
The 4 curved white corners = 1/4 of whole circle with radius 1/2×6
total white area = 4 [1/4 (pi)(3)^2] = 9pi = 28.27

So the shaded green region (S) = total square - total white area

S = 6×6 - 28.27 = 36 - 28.27 = 7.73 sq. m
5 0
3 years ago
J'K'L'M' is a translation of JKLM by vector (-6/2). What are the coordinates of K'? What are the coordinates of M'?
pochemuha

By applying the concept of <em>rigid</em> transformation and the equation of translation we conclude that the coordinates of points K' and M' are (-2, 3) and (-4, 1).

<h3>How to apply a translation to a point on a Cartesian plane</h3>

<em>Rigid</em> transformations are transformations applied onto <em>geometric</em> loci such that Euclidean distance is conserved at every point of the loci. Translations are an example of <em>rigid</em> transformations, whose formula is defined by the following expression:

P'(x, y) = P(x, y) + \vec v     (1)

Where:

  • P(x, y) - Original point
  • P'(x, y) - Resulting point
  • \vec v - Translation vector

If we know that K(x, y) = (4, 1), M(x, y) = (2, -1) and \vec v = (-6, 2), then the coordinates of points K' and M' are:

Point K'

K'(x, y) = (4, 1) + (-6, 2)

K'(x, y) = (-2, 3)

Point M'

M'(x, y) = (2, -1) + (-6, 2)

M'(x, y) = (-4, 1)

By applying the concept of <em>rigid</em> transformation and the equation of translation we conclude that the coordinates of points K' and M' are (-2, 3) and (-4, 1).

To learn more on translations: brainly.com/question/17485121

#SPJ1

7 0
2 years ago
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