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Alina [70]
3 years ago
13

Jeremy has 18 marbles he loses 6 of them what fraction of the marbles dose he have left

Mathematics
2 answers:
prisoha [69]3 years ago
7 0
12/18
6/9
2/3
Make sure you simplify fractions
valina [46]3 years ago
7 0

Ok so we first have 18/18 when he doesn't loose any.

Lets take off 6 from the numerator which is.. 12/18

So.. your answer is 12/18 marbles left.

BUT!! if it were to be simplified... it would be. 2/3

ONLY USE 2/3 IF IT ASKS FOR SIMPLIFIED!!

Hope this helps. :)

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Answer:

y= x/zw

Step-by-step explanation:

Isolate the variable by dividing each side by the factors that dont contain the variable

x = zyw /zw

y=x/zw

3 0
3 years ago
Mrs. Rivera has bars of chocolate in a box. The total mass of bars of chocolate in the box is 3 kilograms. What is the mass in g
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6 0
3 years ago
8,4,6,2 witch is not an composite number
liberstina [14]

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4 is a composite number: 1, 2, 4

6 is a composite number: 1, 2, 3, 6

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7 0
2 years ago
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yawa3891 [41]

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4 0
2 years ago
Guys, Can you please help me with these questions
MakcuM [25]

Answer:

a) w^{13} x^{5} y^{6}

b) \frac{x}{3y^{6} }

Step-by-step explanation:

a) (w^{2} xy^{3} )^{2}(w^{3}x )^{3}

1. Distribute the second power (2) outside the first pair of parenthesis:

(w^{2(2)} x^{2} y^{3(2)} )

= w^{4} x^{2} y^{6} (w^{3}x )^{3}

2. Distribute the third power (3) outside the second pair of parenthesis:

(w^{3(3)} x^{3} )

= w^{4} x^{2} y^{6} w^{9} x^{3}

3. Combine like terms:

w^{13} x^{5} y^{6}

--------------------------------------------

b) \frac{2x^{2} y^{5} }{6xy^{11} }

1. Factor the number 6 (= 2 · 3):

\frac{2x^{2} y^{5} }{2(3)xy^{11} }

2. Cancel the common factor (2):

\frac{x^{2} y^{5} }{3xy^{11} }

3. Cancel out xy^{5} in the numerator an denominator:

\frac{x}{3y^{6} }

hope this helps!

4 0
2 years ago
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