ADD the given the polynomials: (x + 2) + (8x + 4)

Which statements are true about the rectangular pyramid below? Select three options .

sp2606 [1]

Answer:

First, second, and fourth are true.

Step-by-step explanation:

Ok, so let's get to it.

The first statement is true, since 6 * 4 = 24.

The second statement is also true, since the 4 triangles are the 4 sides.

The third statement is false since they aren't congruent since they don't have a consistent ratio.

The fourth one is true, since 24(2) + 18.4 does indeed equal to 66.4

The fifth one is false since only the <u>base </u>has an area of 24.

:)

8 0

3 years ago

Two sacks of silver dollars have 88 dollars between them. The larger one has

Oliga [24]

Answer:

29

Step-by-step explanation:

Since you have a total of 88, you subtract 59 from 88 which gives yoou 29.

8 0

4 years ago

Read 2 more answers

What is tan C ?

MatroZZZ [7]

Answer:

$\frac{1}{2}$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

In the right triangle ABC of the figure, the tangent of angle C is equal to divide the opposite side to angle C (side AB) by the adjacent side to angle C (side BC)

so

$tan(C)=\frac{AB}{BC}$

substitute the given values

$tan(C)=\frac{11}{22}$

simplify

$tan(C)=\frac{1}{2}$

8 0

4 years ago

Bruce arranged 35 pencils on his desk into equal groups of 7 how many groups of pencils are on Bruce's desk

tatyana61 [14]

Answer:

5

Step-by-step explanation:

8 0

4 years ago

Please help with this problem

Andre45 [30]

Answer:

The length of the short side is 14.5 units, the length of the other short side is 18.5 units, and the length of the longest side is 23.5 units.

Step-by-step explanation:

The Pythagorean Theorem

<em> If a and b are the lengths of the legs of a right triangle and c is the length of the hypotenuse, then the sum of the squares of the lengths of the legs is equal to the square of the length of the hypotenuse. </em>

This relationship is represented by the formula:

$a^2+b^2=c^2$

Applying the Pythagorean Theorem to find the lengths of the three sides we get:

$(x)^2+(x+4)^2=(x+9)^2\\\\2x^2+8x+16=x^2+18x+81\\\\2x^2+8x-65=x^2+18x\\\\2x^2-10x-65=x^2\\\\x^2-10x-65=0$

Solve with the quadratic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=1,\:b=-10,\:c=-65:\quad x_{1,\:2}=\frac{-\left(-10\right)\pm \sqrt{\left(-10\right)^2-4\cdot \:1\left(-65\right)}}{2\cdot \:1}\\\\x_{1}=\frac{-\left(-10\right)+ \sqrt{\left(-10\right)^2-4\cdot \:1\left(-65\right)}}{2\cdot \:1}=5+3\sqrt{10}\\\\x_{2}=\frac{-\left(-10\right)- \sqrt{\left(-10\right)^2-4\cdot \:1\left(-65\right)}}{2\cdot \:1}=5-3\sqrt{10}$

Because a length can only be positive, the only solution is

$x=5+3\sqrt{10}\approx 14.5$

The length of the short side is 14.5, the length of the other short side is $14.5+4=18.5$ , and the length of the longest side is $14.5+9=23.5$ .

3 0

3 years ago