Answer:
1 3/7 quarts should be drained off and replaced with pure antifreeze.
1 3/7 ≈ 1.4286
Current amount of antifreeze in quarts is -
30/ 100 × 10 = 3
40% ---> 4 quarts
Let the amount drained of and replaced with antifreeze be x-
The amount left after draining off is 10 − x.
The amount of antifreeze is 30/ 100 (10−x).
30/100(10-x)+x=4
3-3/10x+x=4
3+x(1-3/10)=4
x=1*10/7=1 3/7 quarts
check;
10- 1 3/7 = 8 4/7
=(30/100*8 4/7)+1 3/7
=(3/10 * 60/7) + 10/7
=3*6/7 + 10/7
=28/7
=4
4 liters of pure antifreeze is mixed into 10 quarts.
Answer:
-$7
Step-by-step explanation:
20 - 15 = 5
5 + 5 = 10
10 - 10 = 0
0 - 7 = -7
Answer:
C. The graph of g(x) is shifted 5 units up.
Step-by-step explanation:
The transformation shown shows a vertical translation.
The graph would move f(x) five units up.
Hope this helps.
The answer is 648.
You have to multiply 36 by 18 to get 648
36×18 = 648
Hope that Helps :]
124=100+20+4, 17=10+7
124*17=(100+20+4)(10+7)=1000+200+40+700+140+28=2108
