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Hunter-Best [27]
3 years ago
7

Can i please have help with this question brainliest for answer

Mathematics
1 answer:
zaharov [31]3 years ago
3 0

Answer:

yes I can help

Step-by-step explanation:

which one please

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X + 5 = 1<br> — <br> 4. Step by step please help!!!
Andrej [43]

Answer: x=-8

Step-by-step explanation:

X+5=1-4

X+5=-3

Now subtract 5 from both sides

X=-8

5 0
3 years ago
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Please help I need it now please and thank you
Bingel [31]

Answer:

It would be the first one or second one

Step-by-step explanation:

the answer is up ahead

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3 years ago
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Name
Eddi Din [679]

Answer:

104 Inches

Step-by-step explanation:

Alyssa's blanket contains 7 pink stripes and 6 white  stripes.

Total Number of Stripes =7+6=13

Since each stripe is 8 inches wide.

The width of Alyssa's blanket will be the product of the number of stripes by the width of each stripe.

Therefore:

Width = 13 X 8 Inches =104 Inches

Alyssa's blanket is 104 Inches wide.

4 0
3 years ago
In the formula l2 = h2 +r2, l=25 and r=7, then the value of h is​
Genrish500 [490]

Answer:

18

Step-by-step explanation:

I2=h2+r2

25(2)=h2+7(2)

50=h2+14

-14 -14

36=h2

÷2 ÷2

18=h

8 0
3 years ago
The Student Monitor surveys 1200 undergraduates from 100 colleges semiannually to understand trends among college students. Rece
nlexa [21]

Answer:

A sample size of 385 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

You feel that a reasonable estimate of the standard deviation is 10.0 hours.

This means that \sigma = 10

What sample size is needed so that the expected margin of error of your estimate is not larger than one hour for 95% confidence?

A sample size of n is needed. n is found when M = 1. So

M = z\frac{\sigma}{\sqrt{n}}

1 = 1.96\frac{10}{\sqrt{n}}

\sqrt{n} = 1.96*10

(\sqrt{n})^2 = (1.96*10)^2

n = 384.16

Rounding up:

A sample size of 385 is needed.

7 0
3 years ago
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