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4 years ago

H E L P

Mathematics

1 answer:

Margaret [11]4 years ago

8 0

Answer:

Step-by-step explanation:

-6m + 9

-3(2m - 3)

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Which bar model could be used to show this situation?

9966 [12]

Answer:

C. The attached

Step-by-step explanation:

Our total is 44 dollars. This means that the largest bar, our whole, should be 44.

-> This rules out option D

Now, 4 sweatshirts are being bought. This means the 44 dollars should be broken up into 4 different parts since they all "cost the same amount of money."

-> This rules out options A, C, and D.

This leaves us with the correct option of option C.

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

8 0

2 years ago

Read 2 more answers

Two rectangular sheets of glass have equal perimeters. One has a length of 36 inches and a width w. The other has a length of 26

tia_tia [17]

Answer:

w=5in

Step-by-step explanation:

4 0

3 years ago

Please find the perimeter and area of these shapes

ladessa [460]

Answer:

ABC shaded area = 36 $\pi$ - 72 cm²

ABC shaded area perimeter = $6\pi +12\sqrt{2}$ cm

ABCD area = $\dfrac52 \pi$ cm²

ABCD perimeter = $3\pi +2$ cm

Step-by-step explanation:

Shape ABC

Assuming you want the area and perimeter of the shaded part of the shape only...

Area

Area of a sector = $\dfrac12r^2\theta$ (where r is the radius and $\theta$

⇒ area of a sector = $\dfrac12 \times 12^2\times \dfrac{\pi}{2} =36\pi \ \textsf{cm}^2$

Area of triangle = 1/2 x base x height

⇒ area of triangle = 1/2 x 12 x 12 = 72 cm²

Therefore, area of shaded area = area of sector - area of triangle

⇒ area = 36 $\pi$ - 72 cm²

Perimeter

Arc length = $r\theta$ (where r is the radius and $\theta$

⇒ arc length = $12\times\dfrac12\pi =6\pi \ \textsf{cm}$

Hypotenuse of triangle = $\sqrt{a^2+b^2}$ (where a and b are the legs of the right triangle)

⇒ hypotenuse = $\sqrt{12^2+12^2} =12\sqrt{2}$ cm

Therefore, perimeter = arc length + hypotenuse

⇒ perimeter = $6\pi +12\sqrt{2}$ cm

Shape ABCD

Area

Area of a semicircle = $\dfrac12 \pi r^2$ (where r is the radius)

⇒ area of large semicircle ABC = $\dfrac12 \times \pi \times 2^2=2\pi \ \textsf{cm}^2$

⇒ area of small semicircle AD = $\dfrac12 \times \pi \times 1^2=\dfrac12\pi \ \textsf{cm}^2$

⇒ area of shape ABCD = $\dfrac12 \pi + 2 \pi=\dfrac52 \pi \ \textsf{cm}^2$

Perimeter

1/2 circumference = $\pi r$

⇒ perimeter = $2\pi +2+\pi=3 \pi+2 \ \textsf{cm}$

7 0

2 years ago

1/5 is greater than or equal to x/15

Free_Kalibri [48]

Answer:

most likly greater

Step-by-step explanation:

depends wat X is

6 0

4 years ago

Read 2 more answers

Amari, a basketball statistician

Pepsi [2]

Ok................? is there more to this

5 0

3 years ago