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3 years ago

Evaluate each function. w(a)= a + 4; Find w(1)

Mathematics

2 answers:

Anuta_ua [19.1K]3 years ago

7 0

Answer: 5

because w(a) = a + 4

=> w(1) = 1+ 4 = 5

Step-by-step explanation:

Aneli [31]3 years ago

5 0

Answer: w(a)=5

Step-by-step explanation:

w(a)= a + 4

sub 1 for a.

w(1)= 1 + 4

w(1)= 5

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Which statement is NOT true about the slope of a straight-line graph?

soldi70 [24.7K]

Answer:

Option D. Slope is 1 if the line is vertical

Step-by-step explanation:

we have

Part A) Slope is a measure of the steepness of the line

The statement is true

Because, the steepness of a line is measured by the absolute value of the slope.

Part B) Slope is the ratio of vertical change to horizontal change

The statement is true

Because the formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

Is the ratio of vertical change to horizontal change

Part C) Slope is zero if the line is horizontal

The statement is true

Because If the line is horizontal, the y-coordinate of two points is the same

therefore

The vertical change is equal to zero

Part D) Slope is 1 if the line is vertical

The statement is Not true

Because, if the line is vertical the slope is undefined

5 0

3 years ago

Read 2 more answers

Which graph represents the function<br> f(x) = (x + 4)(x + 1)(x - 3)<br> ?

attashe74 [19]

Answer:

Step-by-step explanation:

The graph that represents the function

f(x) = (x + 4)(x + 1)(x - 3)

crosses the x-axis three times: at x = -4, x = -1, and x = 3

because we apply the zero product rule and found the roots -4, -1, and 3

x+ 4= 0 → x = -4

x+1 = 0 → x = -1

x-3 = 0 → x = 3

8 0

3 years ago

If P(x)= 3x^4 - 5x^3 - 17x^2 + 13x + 6, and P(1)=0, and P(-2)=0, then the factorization of P(x) is?

liberstina [14]

Answer:

P(x) = (x - 1)(x + 2)(x - 3)(3x + 1)

Step-by-step explanation:

Since P(1) = 0 and P(- 2) = 0, then

(x - 1) and (x + 2) are factors of P(x)

(x - 1)(x + 2) = x² + x - 2 ← is also a factor of P(x)

dividing 3 $x^{4}$ - 5x³ - 17x² + 13x + 6 by x² + x - 2 gives

P(x) = (x - 1)(x + 2)(3x² - 8x - 3) = (x - 1)(x + 2)(x - 3)(3x + 1)

5 0

3 years ago

WILL GIVE BRAINLIEST ASAP NEEDED PLS ANSWER HELP

Alika [10]

Answer:

$47,520

Step-by-step explanation:

the area of a polygon is/

A= perimeter X apothem /2

A=500

apothem = 10

500 = (P * 10)/2

P =100

B. 100*7.95 = $795

60*100= 6,000

6,000 * $7.95=

$47,520

7 0

4 years ago

If X and Y are independent continuous positive random

Leni [432]

a) $Z=\frac XY$ has CDF

$F_Z(z)=P(Z\le z)=P(X\le Yz)=\displaystyle\int_{\mathrm{supp}(Y)}P(X\le yz\mid Y=y)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}P(X\le yz)P(Y=y)\,\mathrm dy$

where the last equality follows from independence of $X,Y$ . In terms of the distribution and density functions of $X,Y$ , this is

$F_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy$

Then the density is obtained by differentiating with respect to $z$ ,

$f_Z(z)=\displaystyle\frac{\mathrm d}{\mathrm dz}\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy=\int_{\mathrm{supp}(Y)}yf_X(yz)f_Y(y)\,\mathrm dy$

b) $Z=XY$ can be computed in the same way; it has CDF

$F_Z(z)=P\left(X\le\dfrac zY\right)=\displaystyle\int_{\mathrm{supp}(Y)}P\left(X\le\frac zy\right)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}F_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Differentiating gives the associated PDF,

$f_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}\frac1yf_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Assuming $X\sim\mathrm{Exp}(\lambda_x)$ and $Y\sim\mathrm{Exp}(\lambda_y)$ , we have

$f_{Z=\frac XY}(z)=\displaystyle\int_0^\infty y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=\frac XY}(z)=\begin{cases}\frac{\lambda_x\lambda_y}{(\lambda_xz+\lambda_y)^2}&\text{for }z\ge0\\0&\text{otherwise}\end{cases}$

and

$f_{Z=XY}(z)=\displaystyle\int_0^\infty\frac1y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=XY}(z)=\lambda_x\lambda_y\displaystyle\int_0^\infty\frac{e^{-\lambda_x\frac zy-\lambda_yy}}y\,\mathrm dy$

I wouldn't worry about evaluating this integral any further unless you know about the Bessel functions.

6 0

3 years ago