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podryga [215]
3 years ago
10

In a shipment of airplane parts, 5% are known to be defective. If 21 parts are found to be defective, how many parts are in the

shipment?
Mathematics
1 answer:
horrorfan [7]3 years ago
7 0

We can use ratios and the cross-multiply-divide to find this.



The ratio 21:5 is avaliable via the question. We then need to compare that to the ratio x:100, the 100 being the percent and the x being the number of airplane parts.



21/5 = x/100



We can then solve for x to find the number of airplane parts. First we multiply by 100 on both sides to get 2100/5 = x. Therefore x = 420 and there are 420 airplane parts.

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slava [35]
Given:
estimate = 140
actual = 152

Percent of error = |(estimate - actual)/actual|  * 100%

% of error = |140 - 152| / 152 * 100%
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3 years ago
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James is solving a number puzzle that involves three integers, a, b, and c, where c is a positive integer. The product of a and
m_a_m_a [10]

Given:

Three integers, a, b, and c, where c is a positive integer.

The product of a and b is 6.

The product of a and c is -4.

The product of b and c is -6.

To find:

The values of a,b and c.

Solution:

According to the given information:

ab=6        ...(i)

ac=-4       ...(ii)

bc=-6      ...(iii)

From (ii), we get

a=-\dfrsc{4}{c}          ...(iv)

From (iii), we get

b=-\dfrsc{6}{c}         ...(v)

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\dfrac{24}{6}=c^2

4=c^2

Taking square root on both sides, we get

\pm \sqrt{4}=c

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It is given that c is a positive integer. So, it cannot be negative and the only value of c is c=2.

Putting c=2 in (iv), we get

a=-\dfrsc{4}{2}

a=-2

Putting c=2 in (v), we get

b=-\dfrsc{6}{2}

b=-3

Therefore, the values of a,b,c are a=-2,b=-3,c=2.

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□ x =45.32+32.25
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Answer:

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