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podryga [215]
2 years ago
10

In a shipment of airplane parts, 5% are known to be defective. If 21 parts are found to be defective, how many parts are in the

shipment?
Mathematics
1 answer:
horrorfan [7]2 years ago
7 0

We can use ratios and the cross-multiply-divide to find this.



The ratio 21:5 is avaliable via the question. We then need to compare that to the ratio x:100, the 100 being the percent and the x being the number of airplane parts.



21/5 = x/100



We can then solve for x to find the number of airplane parts. First we multiply by 100 on both sides to get 2100/5 = x. Therefore x = 420 and there are 420 airplane parts.

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F(1)=3f(1)=3 and f(n)=2f(n-1)+3 <br><br> f(n)=2f(n−1)+3 <br><br> then find the value of f(3)
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f(3)=21

Step-by-step explanation:

f(1)=3

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