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OLga [1]
2 years ago
8

54 people are competing in an athletic event. The top 4 competitors receive prize money, with 1st being worth more than 2nd, 2nd

worth more than 3rd, etc. How any ways can the 4 prizes be given
Mathematics
1 answer:
Elanso [62]2 years ago
7 0

Answer:

sets the size of the drawing paper. For size A drawing paper

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Danny worked 30 hours for $18.15/h. The following taxes were deducted from his gross pay: $50.31 in federal taxes, $36.17 in sta
Pavlova-9 [17]
I think the answer is b bc you do 18.15 * 30 then subtract all the taxes 

4 0
3 years ago
Read 2 more answers
How do you estimate 175.32 ÷ 3 =
geniusboy [140]

Answer:

  ≈ 58

Step-by-step explanation:

Estimation usually means you want an answer good to one or maybe two significant figures. That usually means you want to round the numbers involved to one or two significant figures.

Doing that here transforms the problem to 180/3 = 60, an answer with one significant figure.

You can improve the estimate a bit by recognizing that it is a little high (the numerator is higher than 175.32, but the denominator is the same). Since the numerator is high by about 5, the estimate is high by about 5/3 or a little less than 2. A closer estimate will be 60 - 2 = 58.

_____

The degree to which you refine the estimate will depend on the error requirements you have. Certainly an estimate of 60 is within 10% of the true value, so is "close enough" for many purposes.

7 0
3 years ago
What is it plz help me with it ​
victus00 [196]

Answer:

isk

Step-by-step explanation:

3 0
3 years ago
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Si f(x) es igual a raiz de x al cuadrado menos 16 determinar f(5),f(4),f(6),f(3)
Nadusha1986 [10]

Aplicando la función, los valores numéricos son :

f(5) = -11

f(4) = -12

f(6) = -10

f(3) = -13

La función es dada por:

f(x) = (\sqrt{x})^2 - 16  = x - 16

Para los valores numéricos, reemplazamos x, luego:

f(5) = 5 - 16 = -11

f(4) = 4 - 16 = -12

f(6) = 6 - 16 = -10

f(3) = 3 - 16 = -13

Un problema similar es dado en brainly.com/question/7037337

4 0
3 years ago
Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.
Romashka [77]
By definition, the average change of rate is given by:
 AVR =  \frac{f(x2)-f(x1)}{x2-x1}
 We will calculate AVR for each of the functions.
 We have then:

 f(x) = x^2 + 3x interval: [-2, 3]:
 f(-2) = x^2 + 3x  = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18
 AVR = \frac{-2-18}{-2-3}
 AVR = \frac{-20}{-5}
 AVR = 4

 f(x) = 3x - 8 interval: [4, 5]:
 f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7
 AVR = \frac{7-4}{5-4}
 AVR = \frac{3}{1}
 AVR = 3

 f(x) = x^2 - 2x interval: [-3, 4]
 f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8
 AVR = \frac{8-15}{4+3}
 AVR = \frac{-7}{7}
 AVR = -1

 f(x) = x^2 - 5 interval: [-1, 1]
 f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4
 AVR = \frac{-4+4}{1+1}
 AVR = \frac{0}{2}
 AVR = 0


 Answer:
 
these functions from the greatest to the least value based on the average rate of change are:
 f(x) = x^2 + 3x
 
f(x) = 3x - 8
 
f(x) = x^2 - 5
 
f(x) = x^2 - 2x
5 0
3 years ago
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