Answer:
Richard's cumulative GPA = 2.5
Step-by-step explanation:
Richard's cumulative GPA for 3 semesters was 2.0 for 42 credits.
Average = 2
Total credits = 42
Average = sum of terms/total no of terms
2 = sum of terms/42
sum of terms = 84 ....(1)
His fourth semester GPA was 4.0 for 14 course units
Average = 4
Total credits = 14
sum of terms = 56 .....(2)
Average for 4 semesters,

Hence, Richard's cumulative GPA for all 4 semesters is 2.5.
We know that
the area A of the circular cross section of the pipe is
A=pi*r²
D=20 cm------------- > r=D/2=20/2=10 cm
then
A=pi*10²=100*pi cm²
the answer is A=100*pi cm²
Answer:
20
Step-by-step explanation:
a^2 + b^2 = c^2
12^2 + 16^2 = c^2
144 + 256 = c^2
400 = c^2
20 = c
The length of BC = 20