Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
Answer:
a₁ = 1
r = 3
Step-by-step explanation:
Since it’s a geometric series then
a₁ = 1 ( because 1 is the first term of the series)
3/1 = 9/3 = 27/9 = 81/27 = 3 then r=3.
Step-by-step explanation:
Answer:
AX : XB as AB : AC
AX = 5
XB = 4
AC = 6
AB = x
Step-by-step explanation:
5 : 4 as to x : 6
ratios can also be written as fractions...
5/4 = x/6 ..now we have a proportion...so we cross multiply
(4)(x) = (5)(6)
4x = 30
x = 30/4
x = 15/2 <==== AB = 15/2
Answer:
The correct answer is option D. 13
Step-by-step explanation:
From the figure we can see two matrices A and B
<u>To find the sum of a₃₂ and b₃₂</u>
From the given attached figure we get
a₃₂ means that the third row second column element in the matrix A
b₃₂ means that the third row second column element in the matrix B
a₃₂ = 4 and b₃₂ = 9
a₃₂ + b₃₂ = 4 + 9
= 13
The correct answer is option D. 13
