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CaHeK987 [17]
3 years ago
9

Predict if the product will be greater than, less than or equal to the second factor 4/5 x 1 2/5 = y

Mathematics
1 answer:
Radda [10]3 years ago
4 0

Answer:

The product will be less than the second factor.

Step-by-step explanation:

Given the expression

\frac{4}{5}\:\times \:1\frac{2}{5}\:=y

solving to determine the product value

y=\:\frac{4}{5}\times \:\:1\frac{2}{5}

  =\frac{4}{5}\times \frac{7}{5}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}

  =\frac{4\times \:7}{5\times \:5}

  =\frac{28}{5\times \:5}

  =\frac{28}{25}

As the value of the second factor is:

1\frac{2}{5}=\frac{7}{5}=1.4

And the product value is:

y=\frac{28}{25}=1.12

It is clear that the product value 'y = 1.12' is lesser than the second factor value '1.4'.

i.e. 1.12 < 1.4

Thus, the product will be less than the second factor.

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posledela
I believe it’s 16/21 but I’m not sure.

4 0
3 years ago
D is the wrong answer please help :(
Stella [2.4K]

This can be solved by Newton's binomial formula

Tk+1 = (n k) a∧(n-k) b∧k  k+1=7 => k=6, n=11 , a=-3x and b=-2y

T7= (11 6) (-3x)∧(11-6) (-2y)∧6 = (11*10*9*8*7)/(1*2*3*4*5) (-3x)∧5 (-2y)∧6

T7= 462 (-3x)∧5 (-2y)∧6

The correct answer is A.

Good luck!!!


8 0
3 years ago
Read 2 more answers
Need help ...................
aliina [53]

Answer:

with?

Step-by-step explanation:

3 0
3 years ago
Two vectors A⃗ and B⃗ are at right angles to each other. The magnitude of A⃗ is 5.00. What should be the length of B⃗ so that th
creativ13 [48]

Answer:

Length of B is 7.4833

Step-by-step explanation:

The vector sum of A and B vectors in 2D is

C=A+B=(a_1+b_1,a_2+b_2)

And its magnitude is:

C=\sqrt{(a_1+b_1)^2+(a_2+b_2)^2} =9

Where

a_1=Asinx

a_2=Acosx

b_1=Bsin(x+90)

b_2=Bcos(x+90)

Using the properties of the sum of two angles in the sin and cosine:

b_1=Bsin(x+90)=B(sinx*cos90+sin90*cosx)=Bcosx

b_2=Bcos(x+90)=B(cosx*cos90-sinx*sin90)=-Bsinx

Sustituying in the magnitud of the sum

C=\sqrt{(Asinx+Bcosx)^2+(Acosx-Bsinx)^2} =9

C=\sqrt{A^2sin^2x+2ABsinxcosx+B^2cos^2x+A^2cos^2x-2ABsinxcosx+B^2sin^2x} =9

C=\sqrt{A^2(sin^2x+cos^2x)+B^2(cos^2x+sin^2x)}

C=\sqrt{A^2+B^2} =9

Solving for B

A^2+B^2 =9^2

B^2 =9^2-A^2

Sustituying the value of the magnitud of A

B^2=81-5^2=81-25=56

B= 7. 4833

8 0
3 years ago
For the values a = 3.4 and b = 2.6, which are legs of a right triangle, find c, the hypotenuse, to the nearest tenth.
sammy [17]
C^2 = a^2 + b^2
c^2 = 3.4^2 + 2.6^2
c^2 = 11.56 + 6.76
c^2 = 18.32
c = 4.3

answer
c = 4.3
4 0
3 years ago
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