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nalin [4]
2 years ago
14

In a Parallelogram CARS , <C = 5x-20 and <A = 3x+20. Find the value of x ?​

Mathematics
1 answer:
coldgirl [10]2 years ago
6 0

Given that

In a Parallelogram CARS ,∠C = (5x-20)°

∠A = (3x+20)°

angle C and angle A are adjacent angles

We know that

In a Parallelogram the adjacent angles are supplementary.

⇛∠C + ∠A = 180°

⇛ (5x-20)°+(3x+20)° = 180°

⇛5x°-20°+3x°+20° = 180°

⇛(5x°+3x°)+(20°-20°) = 180°

⇛8x°+0 = 180°

⇛8x° = 180°

⇛ x° = 180°/8

⇛ x° = 22.5°

<u>Answer</u>:-The value of x = 22.5°

<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> In parallelogram MATH, m= (3x+ 20) and t= (5x-4) find A

brainly.com/question/11578604?referrer

find the value of x (5x+12) (3x+8) a 10 b 15 c 20 d 25

brainly.com/question/6950381?referrer

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Answer:

e. 0.977

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 478, \sigma = 64

Which of the following is closest to the proportion of daily transactions greater than 350?

This is 1 subtracted by the pvalue of Z when X = 350. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{350 - 478}{64}

Z = -2

Z = -2 has a pvalue of 0.023

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So the correct answer is:

e. 0.977

6 0
3 years ago
Please help with this math problem
zimovet [89]

x=2+½*\sqrt{10}

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Answer:

Solution given:

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2x²-5x-3x+6-3=0

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by using quadratic equation

x=\frac{+8±\sqrt{(-8)²-4*2*3}}{2*2}

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x=\frac{+8+2\sqrt{10}}{4}

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taking negative

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Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

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