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olasank [31]
2 years ago
13

if grant drove his car for 417 miles on 15 gallons of gas. how many miles per gallon does grants car get?

Mathematics
2 answers:
liq [111]2 years ago
8 0

Answer:27.8

Step-by-step explanation:

417/15=27.8

lara [203]2 years ago
3 0

Answer:

27.8 per mile.

Step-by-step explanation:

417 divided by 15 equals 27.8 miles per gallon

miles/ gallon

/ = per

so

417/ 15

27.8 gallons

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Step-by-step explanation:

Just use the graph, this graph is hard to get the answer but you just have to estimate.

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3 years ago
At the beginning of a semester an anonymous survey was conducted on students in a statistics class. Two of the questions on the
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a. Chi-square test of independence

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The chi square statistics is also used to test the hypothesis about the independence of two variables each of which is classified into a number of categories or attributes.

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4 0
3 years ago
A simple random sample of items resulted in a sample mean of . The population standard deviation is . a. Compute the confidence
Varvara68 [4.7K]

Answer:

(a): The 95% confidence interval is (46.4, 53.6)

(b): The 95% confidence interval is (47.9, 52.1)

(c): Larger sample gives a smaller margin of error.

Step-by-step explanation:

Given

n = 30 -- sample size

\bar x = 50 -- sample mean

\sigma = 10 --- sample standard deviation

Solving (a): The confidence interval of the population mean

Calculate the standard error

\sigma_x = \frac{\sigma}{\sqrt n}

\sigma_x = \frac{10}{\sqrt {30}}

\sigma_x = \frac{10}{5.478}

\sigma_x = 1.825

The 95% confidence interval for the z value is:

z = 1.960

Calculate margin of error (E)

E = z * \sigma_x

E = 1.960 * 1.825

E = 3.577

The confidence bound is:

Lower = \bar x - E

Lower = 50 - 3.577

Lower = 46.423

Lower = 46.4 --- approximated

Upper = \bar x + E

Upper = 50 + 3.577

Upper = 53.577

Upper = 53.6 --- approximated

<em>So, the 95% confidence interval is (46.4, 53.6)</em>

Solving (b): The confidence interval of the population mean if mean = 90

First, calculate the standard error of the mean

\sigma_x = \frac{\sigma}{\sqrt n}

\sigma_x = \frac{10}{\sqrt {90}}

\sigma_x = \frac{10}{9.49}

\sigma_x = 1.054

The 95% confidence interval for the z value is:

z = 1.960

Calculate margin of error (E)

E = z * \sigma_x

E = 1.960 * 1.054

E = 2.06584

The confidence bound is:

Lower = \bar x - E

Lower = 50 - 2.06584

Lower = 47.93416

Lower = 47.9 --- approximated

Upper = \bar x + E

Upper = 50 + 2.06584

Upper = 52.06584

Upper = 52.1 --- approximated

<em>So, the 95% confidence interval is (47.9, 52.1)</em>

Solving (c): Effect of larger sample size on margin of error

In (a), we have:

n = 30     E = 3.577

In (b), we have:

n = 90    E = 2.06584

<em>Notice that the margin of error decreases when the sample size increases.</em>

4 0
3 years ago
The cost, y, of red apples can be represented by the equation y = 2x, where x
Temka [501]

Answer:

red apples

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6 0
2 years ago
Write the linear equation
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Answer:

y=-3/2x+4

slope=-3/2

y-int= 4

6 0
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