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sukhopar [10]
3 years ago
5

Fast help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1 me i will give Brainliest if good

Mathematics
1 answer:
emmasim [6.3K]3 years ago
7 0

Using proportions, it is found that there would be 500,000 mites.

  • This question is solved by <em>proportions</em>, using a rule of three.
  • Each dust mite has a length of 2.5 \times 10^{-4} m. How many dust mites could there be in a line of 1.25 \times 10^2 m long?

The <em>rule of three</em> is:

1 dust mite - 2.5 \times 10^{-4} m.

x dust mites - 1.25 \times 10^2 m

Applying cross multiplication:

2.5 \times 10^{-4}x = 1.25 \times 10^2

x = \frac{1.25 \times 10^2}{2.5 \times 10^{-4}}

x = 500000

There would be 500,000 mites.

A similar problem is given at brainly.com/question/24372153

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