Answer:
The mean of sampling distribution of the proportion of the students who prefer later start times for school
μₓ = p = 0.63
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given sample size 'n' =200
given data Of the 200 students surveyed at the local high school, 126 say that they prefer earlier start times for school
sample proportion
The mean of sampling distribution of the proportion of the students who prefer later start times for school
μₓ = p = 0.63
Standard deviation of the proportion
<u>Find time needed for 4/5 mile:</u>
12 miles = 1 hour
1 mile = 1/12 hour
4/5 mile = 1/12 x 4/5 = 1/15 hours
<u>Convert hour to min</u>
1/15 hour = 1/15 x 60 = 4 mins
Answer: He ran for 4 minutes
The confidence interval is given by
where
is the sample mean and
is the standard error of the mean. In turn, the standard error of the mean is
where
is sample size.
We have
The endpoints of the confidence interval correspond to the finite endpoints of the rejection region. That is,
for which we can solve for
. We get
which is the critical value for a confidence level of
.
Answer:
Step-by-step explanation:
A is the correct answer
Answer:
The volume of the cone is 75.36 cm³
Step-by-step explanation:
The rule of the volume of a cone is V = 
π r² h, where
- r is the length of the radius of its base
- h is the height of the cone
In the given figure
∵ The length of the radius of the cone is 3 cm
∴ r = 3 cm
∵ The length of the height of the cone is 8 cm
∴ h = 8 cm
→ Substitute the values of r and h in the rule of the volume above
∵ π ≅ 3.14
∵ V = (3.14)(3)²(8)
∴ V = 75.36 cm³
∴ The volume of the cone is 75.36 cm³
