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Marta_Voda [28]
2 years ago
11

Please give me the correct answer :)

Mathematics
2 answers:
tekilochka [14]2 years ago
8 0

Answer:

-20, -15, -13, -11, -10.

p≥−10

hope this helps! :)

tresset_1 [31]2 years ago
5 0
0, -5, -7, -9, -10

For the bottom thing:

p(-10)=90

Hope this helps!!
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Product of two natural numbers p and q is 590 and their hcf is 59. how many set of values of p and q is possible
djverab [1.8K]

\text{Let the product of two natural numbers p and q is 590, and their HCF is 59}\\
\\
\text{we know that the product of LCM and HCF of any two numbers is equal}\\
\text{to the product of the numbers. that is}\\
\\
\text{HCF}\times \text{ LCM}=p\times q\\
\\
\Rightarrow 59 \times \text{LCM}=590\\
\\
\Rightarrow \text{LCM}=\frac{590}{59}\\
\\
\Rightarrow \text{LCM}=10\\
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\text{for any two natural numbers, their Least Common Multiple (LCM) is always}

\text{greater than their HCF.}\\
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\text{but here we can see that }LCM

Hence there is no such natural numbers exist.

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