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vampirchik [111]
3 years ago
8

Consider the following equations: −x − y = 1 y = x + 3 If the two equations are graphed, at what point do the lines representing

the two equations intersect? (4 points) (−1, 2) (−2, 1) (1, −2) (2, −1)
Mathematics
1 answer:
ASHA 777 [7]3 years ago
5 0

Equation 1: -x-y = 1y, -x = 2y

Equation 2: 1y = x+3 , y = x+3

Substitute equation 2 into equation 1

-x = 2y

-x = 2(x+3)

-x = 2x + 6

-3x = 6

x = -2

Substitute x=-2 into equation 2

y = x+3

y = -2+3

y = 1

So, (x,y) = (-2,1)

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alexira [117]

You can obtain information about the mean population by taking a random sample of it and taking the average of that sample. The Law of big Numbers says that the bigger the sample, the more likely we will be closer to the real mean value. In other words, the margin of error is less likely to be big.

7 0
3 years ago
A Jewelry Company sells a bracelet and gives customers the option to purchase charms to add to the bracelet. The expression 60+2
vlabodo [156]

Answer: the price per charm

Step-by-step explanation:

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7 0
3 years ago
Kaden, Keith, and Kipp compete in a series of daily 3-way races. For each race, the probability that Kaden wins is 1/6, the prob
BlackZzzverrR [31]

9514 1404 393

Answer:

  3/5

Step-by-step explanation:

Let a, b, c represent the probability of a win by Kaden, Keith, and Kipp, respectively.

  P(bc' | a') = P(a'bc')/P(a')

  P(bc' | a') = (1/2)/(1 -1/6) = (3/6)/(5/6) = 3/5

The probability is 3/5 that Keith beats Kipp when Kaden doesn't win.

4 0
3 years ago
Somebody please help me on multiple step equations with parenthesis.
mash [69]

Answer:

k = 8

Step-by-step explanation:

8(10 - k) = 2k

First, distribute within the parenthesis,

80 - 8k = 2k

Add 8k to both sides of the equation

80 = 10k

Divide both sides by 10 to get your answer

8 = k

I hope this helps :)

4 0
3 years ago
How do you factor the trinomial 3p^2-2p-5
asambeis [7]
Use slip and slide method
p^2-2p-15
(p-5)(p+3)

(p-5/3)(p+3/3)
(p-5/3)(p+1)
(3p-5)(p+1)

Final answer: (3p-5)(p+1)
7 0
3 years ago
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