The given information permits us to calculate the circumference (C) of the wheel as follows

Then (as you said correctly!) the same wheel will move

after 16 rolls.
The answer is c because you have to say 27 minus the number minus 3
So the expression is:

You can combine like terms, which are terms that contain the same variables raised to the same power. That means you can combine the two

.

The other terms can't be combined.
Your final answer should be

.
Answer:




Step-by-step explanation:
Given


Required
Select Yes or No for the given options

Considering the sine of angle B, we have:


Make AB, the subject


Considering the cosine of angle B, we have:


Make AB the subject


Considering the cosine of angle B, we have:


Make AB the subject


<em>This has been shown in (c) above</em>
The formula to finding a discriminant would be b^2-4ac, the b value of this trinomial being -5, the a value being 2, the c value being 3. Then, you plug the values in the equation and solve: (-5)^2-4(2)(3)
This would simplify to 1, meaning there are two solutions since the discriminant value is positive. If it is 0, there is one solution, if it is negative, then there are no real solutions.