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3 years ago

0.04 is 1/10 0f what

Mathematics

2 answers:

PSYCHO15rus [73]3 years ago

8 0

0.04, or 4 hundredths is 10 percent of 0.40
10 times 0.04 gives you 0.40

cupoosta [38]3 years ago

5 0

0.04, or 4 hundredths is 10 percent of 0.40
10 times 0.04 gives you 0.40

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Find the length of the leg(s) of a right triangle, to the nearest hundredth, if both legs are equal and the hypotenuse is 10.

charle [14.2K]

Answer:

7.07 units

Step-by-step explanation:

Use the Pythagorean theorem for the right triangle:

$\text{hypotenuse}^2=\text{leg}_1^2+\text{leg}_2^2,\\ \\c^2=a^2+b^2.$

If a = x, b = x, and c = 10, then

$10^2=x^2+x^2,\\ \\100=2x^2,\\ \\x^2=50,\\ \\x=\sqrt{50}=5\sqrt{2}\approx 7.07\ units.$

7 0

3 years ago

PLEASE HELP ASAP! The quotient of two rational numbers is positive. What can you conclude about the signs of the dividend and th

Anon25 [30]

Answer:

They either both have to be positive or negative.

Step-by-step explanation:

1 / 1 = 1

-1 / -1 = 1

This gets you positive, when both dividend and divisors are positive or negative.

-1 / 1 = -1

1 / -1 = -1

This gets you negative, when both dividend and divisors are different signs.

3 0

3 years ago

Read 2 more answers

An 18 foot ladder touches a building 14 feet up the wall.

saw5 [17]

Check the picture below.

make sure your calculator is in Degree mode.

5 0

3 years ago

Read 2 more answers

Match the expressions with their equivalent simplified expressions.

Tasya [4]

Answer:

$\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}$

Step-by-step explanation:

$\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}} =\sqrt[4]{\frac{(2^4)(x^{6-2})(y^{4-8})}{(3^4)}} =\sqrt[4]{\frac{2^4x^4y^{-4}}{3^4}} =\frac{2xy^{-1}}{3}=\frac{2x}{3y}$

$\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} =\sqrt[4]{\frac{(3^4)(x^{2-6})(y^{10-6})}{(2^4)}} =\sqrt[4]{\frac{3^4x^{-4}y^{4}}{2^4}} =\frac{3x^{-1}y^1}{3}=\frac{3y}{2x}$

$\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}} =\sqrt[3]{\frac{(4^3)(x^{8-2})(y^{7-10})}{(5^3)}} =\sqrt[3]{\frac{4^3x^6y^{-3}}{5^3}} =\frac{4x^2y^{-1}}{5}=\frac{4x^2}{5y}$

$\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}} =\sqrt[5]{\frac{(3^5)(x^{17-7})(y^{16-21})}{(2^5)}} =\sqrt[5]{\frac{3^5x^{10}y^{-5}}{2^5}} =\frac{3x^2y^{-1}}{2}=\frac{3x^2}{2y}$

$\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} =\sqrt[5]{\frac{(2^5)(x^{12-7})(y^{15-10})}{(3^5)}} =\sqrt[5]{\frac{2^5x^{5}y^{5}}{3^5}} =\frac{2x^1y^{1}}{3}=\frac{2xy}{3}$

$\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}} =\sqrt[4]{\frac{(2^4)(x^{10-2})(y^{9-17})}{(4^4)}} =\sqrt[4]{\frac{2^4x^{8}y^{-8}}{4^4}} =\frac{2x^{1}y^{-1}}{4}=\frac{x}{2y}$

Thus,

3 0

3 years ago

AFTER distributing the 5, what will the constant be in the following equation?<br> 5(x+3)=-25

qwelly [4]

X = -8
Constant will be x

4 0

2 years ago