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Ber [7]
2 years ago
12

Select the correct answer.

Mathematics
1 answer:
gulaghasi [49]2 years ago
7 0
The correct answer is B.
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PLEASE PLEAE PLEASE HELP
scoundrel [369]
She bought 4 coffees! :)
7 0
3 years ago
Type integer or fraction as answer simplify answer
vova2212 [387]

Answer:

51/28

Step-by-step explanation:

Start by making common denominators.

<u>7</u>       <u>2</u>

4       4

Now subtract the two.

7   -    2  = <u>5</u>

                 4

Now you have to make common denominators for the second part, 4/7

<u>16</u>  +  <u>35</u> = <u>51</u>

28     28    28

brainliest is nice ig

7 0
3 years ago
Help me find the numbers for the function table
mamaluj [8]

Answer:

0,4,7

Step-by-step explanation:

you take the input number like 8 subtract it by 4 to get the output

5 0
2 years ago
Read 2 more answers
Let p: The whole number has one digit.
Alex73 [517]

The statement "The whole number has one digit if and only if the whole number is less than 10" is true for converse statement. Then the correct option is C.

<h3>What are converse statements?</h3>

A inverse statement is one that is derived by opposing the supposition and result of a relative clause.

Let p: The whole number has one digit.

Let q: The whole number is less than 10.

The statement "The whole number has one digit if and only if the whole number is less than 10" is true for converse statement.

If p → q, then, q → p

Then the correct option is C.

More about the converse statements link is given below.

brainly.com/question/18152035

#SPJ1

4 0
1 year ago
Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2. ​
insens350 [35]

Answer:

x->-2^{-}, p(x)->-\infty and as x->-2^{+}, p(x)->-\infty

Step-by-step explanation:

Given

p(x) = \frac{x^2-2x-3}{x+2} -- Missing from the question

Required

The behavior of the function around its vertical asymptote at x = -2

p(x) = \frac{x^2-2x-3}{x+2}

Expand the numerator

p(x) = \frac{x^2 + x -3x - 3}{x+2}

Factorize

p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}

Factor out x + 1

p(x) = \frac{(x -3)(x + 1)}{x+2}

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

x -> -2^{-} Say x = -3

p(x) = \frac{(x -3)(x + 1)}{x+2}

p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

x->-2^{-}, p(x)->-\infty

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: x>-2

Say x = -2.1

p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

x->-2^{+}, p(x)->-\infty

So, the behavior is:

x->-2^{-}, p(x)->-\infty and as x->-2^{+}, p(x)->-\infty

6 0
3 years ago
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