In the proof we see that ∠EGF is congruent to ∠HGK because they are vertical angles. We also see that KG is congruent to FG because G is the midpoint. Additionally we have that ∠F is congruent to ∠K because they are alternate interior angles. We have two angles and the side between them, or ASA.
Answer:
5
Step-by-step explanation:
6788990-0987654321234567890-=-09876543211234567890-
Answer:
- Graph B has one real root.
- Graph A has a negative discriminant
- Graph C has an equation with the coefficients a=1, b=4, c=-2.
Step-by-step explanation:
The number of real roots is the number of places where the graph intersects the x-axis. When the discriminant is negative, there are none. Graph A does not cross the x-axis, so has a negative discriminant.
Graph B intersects the x-axis at one point, so it has one real root.
Graph C has two real roots, consistent with the positive discriminant associated with the given coefficients:
_____
For quadratic ...
the discriminant is ...
and the roots are ...
Then the roots are only real when the discriminant is non-negative. The square root function will not give real values for a negative argument.
I need the pictures but the y slope is the top I hope this helps