Answer:
I got x<equal to -11 or x>equal to4
Step-by-step explanation:
x^2+15x+44=0
(x+4)(x+11)=0(Factor left side of equation)
x+4=0 or x+11=0(Set factors equal to 0)
x=−4 or x=−11
Check intervals in between critical points. (Test values in the intervals to see if they work.)
x<−11(Works in original inequality)
−11<x<−4(Doesn't work in original inequality)
x>−4(Works in original inequality)
Answer:
x<−11 or x>−4
Answer:
A. a = 10
B. m<FNT = 120°
C. m<KTU = 60°
Step-by-step explanation:
A. (7a + 50)° and (14a - 20)° are corresponding angles. Therefore:
(7a + 50)° = (14a - 20)°
Use this equation to find the value of a
7a + 50 = 14a - 20
Combine like terms
7a - 14a = - 50 - 20
-7a = -70
Divide both sides by -7
-7a/-7 = -70/-7
a = 10
B. m<FNT = (14a - 20)° (alternate interior angles are congruent)
Plug in the value of a
m<FNT = 14(10) - 20
m<FNT = 140 - 20
m<FNT = 120°
C. m<KTU + (14a - 20)° = 180° (linear pair)
Plug in the value of a
m<KTU + 14(10) - 20 = 180
m<KTU + 120 = 180
m<KTU + 120 - 120 = 180 - 120
m<KTU = 60°
Start out by adding 50 to both sides.
2x - 50 + 50 = 150 + 50
which simplifies to
2x = 200
then divide both sides by 2
2x ÷ 2 = 200 ÷ 2
which simplifies to
x = 100
And that is your answer! Hope this helps :)
Answer:
Step-by-step explanation:
For 5 we need to use sine law.
The thing about sine law is that we need to look at the triangle sides that are in front of the angles.
In this case: <B = 30°
the triangle side that is in front of this angle is AC which is 4 cm.
Then we got <C = 61°, and the triangle side in front of it is AB, which is what we need to find.
According to sine law:
Notice that you need to be consistent. If you start writing that the angle is in the numerator, it needs to be in the numerator on the other side of the equation.
Solving it would give us:
(AB )(sin 30) = (sin 61)(4)
AB = 6.9969 cm
to the nearest tenth it's 7.0 cm
Question 6:
Wow it's pretty crowded, but they probably want us to use sine law as well. Let's write what we know:
<C = 12°
<B = 107°
AB = 21 yd
AC = ?
Apply it to the formula: sin(angle) / the triangle side in front of it.
(sin 107)(21) = (sin 12)(AC)
AC = 96.59
to the nearest tenth AC = 96.6 yd
