Your answer should be C or the third one
3.
1 & E
2 & A
3 & C
4 & B
5 & D
4.
1 & E
2 & C
3 & A
4 & B
5 & D
5.
1. 3.002 is less than 3.02
2. -5/12 is greater than -7/12
3. 3/5 is equal to 0.6
10.
1. B
2. D
3. C
4. A
(Not 100% sure on those 4)
13.
The circumference is double the radius.
We can write this as r = C/3.14 x 2
3.14 x 2 = 6.28 and we know the circumference is 50.24
r = 50.24/6.28
r = 8
The answer is 10π using pythagoreans theorem
<h3>Given</h3>
4 hundreds flats; 5 tens rods; 2 ones cubes
<h3>Find</h3>
The number of hundreds flats in each of 2 equal piles
<h3>Solution</h3>
When 4 flats are divided into two equal groups, each group will have ...
... 2 flats
_____
You can imagine doing this the way a card dealer might: first put 1 flat in each of 2 piles, then do the same for the remaining 2 flats. Each pile will end up with 2 flats.
— — — — —
You will have a problem if you continue with the tens rods. There is an odd number of those, so one of them will have to be exchanged for 10 ones cubes.