Answer:
The answer is below
Step-by-step explanation:
The question is not complete. A complete question is in the form:
A letter is chosen at random from the letters of the word EXCELLENT. Find the probability that letter chosen is i) a vowel ii) a consonant.
Solution:
The total number of letters found in the word EXCELLENT = 9
i) The number of vowel letters found in the word EXCELLENT = {E, E, E} = 3
Hence, probability that letter chosen is a vowel = number of vowels / total number of letters = 3 / 9 = 1 / 3
probability that letter chosen is a vowel = 1/3 = 0.333 = 33.3%
ii) The number of consonant letters found in the word EXCELLENT = {X, C, L, L, N, T} = 6
Hence, probability that letter chosen is a consonant = number of consonant / total number of letters = 6 / 9 = 2 / 3
probability that letter chosen is a consonant = 2/3 = 0.667 = 66.7%
Y=mx+b
First use the two point slope formula to find m
(y2-y1)/(x2-x1)
(2-0)/(-9-9)
2/-18
1/-9=m
Next use the point slope formula to find the answer
y-y1=m(x-x1)
y-0=1/-9(x-9)
Now use Distributive Property
y-0=1/-9(x)+1/-9(-9)
y-0=1/-9x+1
Your answer would be
y=-1/9x+1
Answer: its b
Step-by-step explanation: i solved it through seconesion
12.36% I think sorry if its wrong ;-;
Answer:
3000
Step-by-step explanation: