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Taya2010 [7]
3 years ago
13

Carly and Simon are renting formal clothes for a wedding.

Mathematics
2 answers:
aliya0001 [1]3 years ago
8 0

The answer should be C

Cerrena [4.2K]3 years ago
7 0

Answer:

C. y = 21x+90

Step-by-step explanation:

Let x be the number of hours. Each hour costs 21 dollars, so the cost of all the hours would be 21x. Then add a fixed fee of 90 to get C, y = 21x+90

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The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont
BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)

and its cumulative distribution function (CDF) is

\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so  A∩B = B and  

\bf P(A | B) = P(B)P(B) = (P(B))^2

We have  

\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237

hence,

\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection =  </em>

\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021

5 0
3 years ago
Solve for x in the equation 4x-3(4x-5)=3
lubasha [3.4K]

Answer: x=3/2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
HELP ME! FAST! Please help me! ASAP! PLEASE! SOMEONE HELP ME!
Harrizon [31]
I hope this helps you

5 0
3 years ago
What’s the answer to 4x+120
s2008m [1.1K]
You cannot find the answer to 4x+120 without knowing x, otherwise it is simplified as far as it can be
4 0
3 years ago
Read 2 more answers
Which Theorem do you use to solve for D?
mixas84 [53]

Answer:

D + 50 - 20 = 70

D = 70

Step-by-step explanation:

5 0
3 years ago
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