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Eddi Din [679]
3 years ago
15

An airplane travels 6032 kilometers against the wind in 8 hours and 7312 kilometers with the wind in the same amount of time. Wh

at is the rate of the plane in
still air and what is the rate of the wind?
Mathematics
1 answer:
Vladimir79 [104]3 years ago
3 0

Answer:

The rate of plane in still air is 834 km/hr and the rate of wind is 80 km/hr.

Step-by-step explanation:

The airplane travels 6032 km in 8 hours against the wind.

So, u -v = \frac{6032}{8} = 754 ........ (1) {Where u is the speed of plane in still air and v is the wind speed}

Again, the airplane travels 7312 km in 8 hours with the wind.

So, u +v=\frac{7312}{8} =914 ........ (2)

Now, adding equations (1) and (2) we get,

2u = 1668

⇒ u = 834 km per hour.

So, from equation (1), we get  

v = u - 754 = 834 - 754 = 80 km per hour.

Therefore, the rate of the plane in still air is 834 km/hr and the rate of wind is 80 km/hr. (Answer)

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AB is horizontal. The slope of a horizontal line is zero.
8 0
3 years ago
The shark are fed three times a day during the morning feeding 2/15 of a ton. During the afternoon feeding the weight of fish fe
UNO [17]

Answer:

The shark are fed \frac16 \ ton of fish during the night.

Step-by-step explanation:

Given:

Weight of fish fed in the morning = \frac{2}{15}\ ton

Also Given:

During the afternoon feeding the weight of fish fed will be 1/15 of a ton more than the fish fed during the morning.

Weight of fish fed in the afternoon = \frac{2}{15}+\frac{1}{15}=\frac{2+1}{15}=\frac{3}{15}\ ton

Total fish fed in whole day = \frac12 \ ton

We need to find the Weight of fish fed in the night.

Solution:

Now we can say that;

Weight of fish fed in the night can be calculated by by subtracting Weight of fish fed in the morning and Weight of fish fed in the afternoon from Total fish fed in whole day .

framing in equation form we get;

Weight of fish fed in the night = \frac{1}{2}-\frac{2}{15}-\frac{3}{15}= \frac{1}{2}-(\frac{2}{15}+\frac{3}{15})=\frac{1}{2}-\frac{2+3}{15}= \frac{1}{2}-\frac{5}{15} = \frac{1}{2}-\frac{1}{3}

Now we will use LCM for making the denominator common we get;

Weight of fish fed in the night = \frac{1\times3}{2\times3}-\frac{1\times2}{3\times2} = \frac{3}{6}-\frac{2}{6}

Now denominator are common so we will solve the numerators.

Weight of fish fed in the night = \frac{3-2}{6}=\frac16 \ ton

Hence The shark are fed \frac16 \ ton of fish during the night.

3 0
3 years ago
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olchik [2.2K]

Answer:

Percent Decrease = 20% Decrease

Step-by-step explanation:

To find percentage decrease, we will use a simple formula shown below:

Percentage Decrease/Increase = \frac{New-Old}{Old}*100

Where

New is the latest number of members (which is 24)

Old is the initial number of members (which is 30)

<em>Note: the multiplication by a factor of "100" brings the answer to a percentage</em>.

Now, lets substitute the numbers and figure out the percentage decrease:

\frac{New-Old}{Old}*100\\\frac{24-30}{30}*100\\\frac{-6}{30}*100\\-0.2*100\\-20

So, it comes to -20, which is a decrease of 20%

7 0
3 years ago
What are the units for the spring constant, k?
svlad2 [7]
The spring constant, k, in Hooke's Law has units of Newton per meter since it is a constant for the force applied per unit of length. The spring constant measures how strong and stiff the spring is. Hope this answers the question. Have a nice day.
3 0
3 years ago
BRAINLIEST MARKED!! PLSS HELP ASAPP!! Plz show all work!!!
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Answer:

551.7

Step-by-step explanation:

it is the square + the circle

15*25+πr²

375+π(15/2)²

375+π225/4

375+176.625=551.625

7 0
3 years ago
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