Answer what grade i would recommend to use Socratic just take pic of it ad it will search all around for it
Step-by-step explanation:
The values of (x, y) are (-5, 1), if the equations
and
are solved by elimination method.
Step-by-step explanation:
The given is,
................................(1)
.....................................(2)
Step:1
Equation (2) is multiplied by -1 ( Eqn (2) × -1 )
..................................(3)
Step:2
Substrate the equation (1) and equation (3),
![x-5y=-10](https://tex.z-dn.net/?f=x-5y%3D-10)
![x-y=-6](https://tex.z-dn.net/?f=x-y%3D-6)
( - )
After the Subtraction equation becomes,
![(x-x)+(-5y+y)=(-10+6)](https://tex.z-dn.net/?f=%28x-x%29%2B%28-5y%2By%29%3D%28-10%2B6%29)
![(0)+(-4y)=(-4)](https://tex.z-dn.net/?f=%280%29%2B%28-4y%29%3D%28-4%29)
![-4y=-4](https://tex.z-dn.net/?f=-4y%3D-4)
![y=1](https://tex.z-dn.net/?f=y%3D1)
Step:3
By using y value find value of x,
![x-5y=-10](https://tex.z-dn.net/?f=x-5y%3D-10)
![x-(5)(1)=-10](https://tex.z-dn.net/?f=x-%285%29%281%29%3D-10)
![x=-10+5](https://tex.z-dn.net/?f=x%3D-10%2B5)
![x=-5](https://tex.z-dn.net/?f=x%3D-5)
Step:4
Check for solution,
![-x+y=6](https://tex.z-dn.net/?f=-x%2By%3D6)
![-(-5)+1=6](https://tex.z-dn.net/?f=-%28-5%29%2B1%3D6)
![6=6](https://tex.z-dn.net/?f=6%3D6)
Both sides are equal so answer is corrected
Result:
The values of (x, y) are (-5, 1), if the equations
and
are solved by elimination method.
The answer to this question is 3976%
Answer:
t-6
Step-by-step explanation:
41-35=6
35-29=6
29-23=6
This shows that the pattern is subtracting 6 from the term each time so the answer is t-6
Good question!
Since we know the value of the hypotenuse and we want to find the value opposite of the angle given, We will use Sine.
First Step: write out the equation Sin(40)= c/15
Second Step: punch in Sin(40) (MAKE SURE YOUR CALC IS IN DEGREE MODE!!!!!) in your calculator and then multiply it by 15
(Sin(40)) x 15 = c
Final Step: after multiplying them together you'll get an answer of 9.64!
So the answer is the second one! hope I helped (: