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Naily [24]
3 years ago
9

What is the product of a+3 and −2a2+15a+6b2?

Mathematics
2 answers:
zhannawk [14.2K]3 years ago
8 0

Answer:

-2a³+9a²+45a+6ab²+18b²

Step-by-step explanation:

(a+3)(-2a²+15a+6b²)

Distribute the a:

-2a³+15a²+6ab²

Then distribute the 3:

-6a²+45a+18b²

Now add both of the results together:

-2a³+15a²+6ab²-6a²+45a+18b²

Combine like terms:

-2a³+9a²+45a+6ab²+18b²

o-na [289]3 years ago
6 0

Answer:

  (c)  −2a^3+9a^2+45a+6ab^2+18b^2

Step-by-step explanation:

Examination of the answer choices shows us we only need to be concerned with the a^2 term and the b^2 term.

The a^2 term will be the sum of products ...

  3(-2a^2) +a(15a) = (-6 +15)a^2 = +9a^2

The b^2 term will be the product ...

  3(6b^2) = 18b^2

These terms are sufficient to identify choice C as the correct answer choice.

_____

<em>Additional comment</em>

It can often work well to develop the product of polynomials by considering the terms that must contribute to a given product term. For a term containing a^2, the product of polynomial terms can have that degree if and only if it is the product of a constant and an a^2 term, or the product of two a^1 terms. The ways those products can be achieved are shown in the above working.

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tresset_1 [31]

Answer:

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Hope it helps!!!

Step-by-step explanation:

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3 years ago
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Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

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Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

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3 0
3 years ago
Judith went shopping with $50 and spent $45. What percentage of her money did she<br> spend?
juin [17]

Answer:

90%

Step-by-step explanation:

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5 0
4 years ago
Read 2 more answers
Write an expression to represent the phrase, "6 of one thing plus half a dozen of the other"
yawa3891 [41]
'of' means multiply
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6 of one thing means 6 times x
plus  means ad
half a dozen of another mean 6 times y

they are added

6x+6y


2 variables
it says 'of the other' so they are diferent
4 0
4 years ago
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