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2 years ago

CAN SOMEONE HELP ME PLEASE ASAP!

Mathematics

2 answers:

Misha Larkins [42]2 years ago

8 0

Answer:

the answer is 21 cm

Step-by-step explanation:

as doing by formulae

cupoosta [38]2 years ago

7 0

The width is 21 centimeters.

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Do you guys know what is after you become an expert??

adell [148]

Answer:

Ace is the next level after expert.

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2 years ago

Write the following as an equation. Then solve.

vekshin1

$4 \times 8 = 28 = 7 \times 4 = 28$
So this means they just fliped the numbers around

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3 years ago

A whale is at the surface of the ocean to breathe. The whale swims down 300 feet to feed. The whale swims down 150 more feet mor

Licemer1 [7]

0-300-150=-450 feet
-450 feet is the whale’s elevation

4 0

2 years ago

Read 2 more answers

60 POINTS AND BRAINLIEST!!!!!

ser-zykov [4K]

SOLUTION:

3y - 24 = 237

3y = 237 + 24

3y = 261

y = 261 / 3

y = 87

Hope this helps! :)
Have a lovely day! <3

5 0

2 years ago

The American Water Works Association reports that the per capita water use in a single-family home is 67 gallons per day. Legacy

inessss [21]

Answer:

We conclude that the null hypothesis is rejected which means residents of Legacy Ranch use less water on average.

Step-by-step explanation:

We are given that the American Water Works Association reports that the per capita water use in a single-family home is 67 gallons per day.

Twenty-three owners responded, and the sample mean water use per day was 63 gallons with a standard deviation of 8.1 gallons per day.

Let $\mu$ = average water usage by residents of Legacy Ranch.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 67 gallons {means that the residents of Legacy Ranch uses more or equal to 67 gallons water on average}

Alternate Hypothesis, $H_A$ : $\mu$ < 67 gallons {means that the residents of Legacy Ranch use less water on average}

The test statistics that will be used here is One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean water use per day = 63 gallons

s = sample standard deviation = 8.1 gallons

n = sample of responded = 23

So, test statistics = $\frac{63-67}{\frac{8.1}{\sqrt{23} } }$ ~ $t_2_2$

= -2.368

The value of the test statistics is -2.368.

Now at 0.025 significance level, the t table gives critical value of -2.074 at 22 degree of freedom for left-tailed test. Since our test statistics is less than the critical values of t as -2.368 < -2.074, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the residents of Legacy Ranch use less water on average.

8 0

3 years ago