Answer:
33 and 19
Step-by-step explanation:
there are 33 numbers between one and one hundred divisible by 3 and 19 numbers divisible by 5
Given that the sequence is:
1,2,4,8,32
the recursive formula will be found as follows:
first term is=1
the sequence can be written as:
1,2,4,8,32
=(1*2^0),(1*2^1),(1*2^2),(1*2^3),(1*2^4)
thus the recursive formula will be
an=a1(r)^(n-1)
plugging the values we get:
an=1(2)^(n-1)
The valued of the expression is 1 .
Step-by-step explanation:
see the answer in the pic
