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alisha [4.7K]
3 years ago
12

Simplify. 54+4(3/4−1/2)2

Mathematics
1 answer:
Effectus [21]3 years ago
7 0

Answer:

56

Step-by-step explanation:

54 + 4(3/4 − 1/2)2

=> 54 + 4(1/4)2

=> 54 + (1)2

=> 54 + 2

=> 56

Therefore, 56 is our answer.

Hoped this helped.

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Grace has a 15 inch diameter bicycle tire. How many revolutions will it make traveling 500 feet?
Brums [2.3K]

Answer:

Revolution = 127.24 revolutions

Step-by-step explanation:

<em><u>Circumference of the tire = πD</u></em>

Where D = 15 inch

So,

C = 15π = 47.1 inch

<u><em>In feets:</em></u>

47.1 inch = 3.93 feet.

So, <u>one revolution = 3.93 feet</u>

<u><em>Travelling 500 feet will make the following revolutions:</em></u>

Revolution = 500 feet/3.93 feet

Revolution = 127.24 revolutions

5 0
3 years ago
Please may someone help with c
german

Step-by-step explanation:

Distance between two villages = d

(a) \:  \frac{4}{5}  \: of \: d =  \frac{4}{5} d \\  \\ (b) \:  \frac{3}{4}  \: of \: d =  \frac{3}{4} d  \\  \\ (c) \: \frac{4}{5} d -   \frac{3}{4} d = 1.5 \\  \\  \therefore \:   \bigg(\frac{4}{5} -   \frac{3}{4} \bigg) d = 1.5 \\  \\ \therefore \:   \bigg(\frac{4 \times 4 - 3 \times 5}{5 \times 4} \bigg) d = 1.5 \\  \\ \therefore \:   \bigg(\frac{16- 15}{20} \bigg) d = 1.5 \\  \\ \therefore \:   \bigg(\frac{1}{20} \bigg) d = 1.5 \\  \\ \therefore \: d = 1.5 \times 20 \\  \\ \:  \:  \:  \:  \:  \huge \orange{ \boxed{{ \therefore \: d = 30}}}

4 0
3 years ago
Which is the correct first step in finding the height of a cylinder with a volume of 178 cubic inches and a radius of 8 inches?
Strike441 [17]

Answer:

C

Step-by-step explanation:

Ccc

3 0
3 years ago
X+1.793=2.42
Varvara68 [4.7K]
The right answer is
0.627
4 0
2 years ago
Please help with this I am completely stuck on it
vaieri [72.5K]

Answer:

f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4

Step-by-step explanation:

Given:

The function, H(x)=\sqrt[3]{6x^{2}-4}

Solution 1:

Let f(x)=\sqrt[3]{x}

If f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}, then,

\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4

Solution 2:

Let f(x)=\sqrt[3]{x-4}. Then,

f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}

Similarly, there can be many solutions.

7 0
3 years ago
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