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chubhunter [2.5K]
3 years ago
14

write a function g whose graph represents the indicated transformation of the graph of f. f(x)=|x+1|-3; horizontal stretch by a

factor of 9.​
Mathematics
1 answer:
dybincka [34]3 years ago
6 0

Answer:

f(x) = |\frac{1}{9}(x+1)|-3

Step-by-step explanation:

The value representing the horizontal scaling must be placed inside the absolute value, and we need to put () around x - 1 to change the horizontal shift as well. And remember that we must use the reciprocal in the function, so instead of writing y = |9(x+1)|-3, we need to write y = |\frac{1}{9}(x+1)|-3.

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A 60 inch board is to be cut into three peices so that the second peice is four times as long as the first peice and the third p
Lostsunrise [7]

Answer:

The first piece is 6 inches, the second piece is 24 inches, and the third piece is 30 inches

Step-by-step explanation:

Since the second piece is 4 times longer than the first one, it will be represented by 4x.

The third piece is 5 times as long as the first one, so it will be represented by 5x.

Create an equation adding up the 3 x values up to 60:

x + 4x + 5x = 60

Add like terms and solve for x:

10x = 60

x = 6

So, the first piece is 6 inches.

Then, plug in 6 for x to find the lengths of the second and third pieces.

4x

4(6)

= 24

The second piece is 24 inches

5x

5(6)

= 30

The third piece is 30 inches

So, the first piece is 6 inches, the second piece is 24 inches, and the third piece is 30 inches

6 0
3 years ago
Cate and elena were playing cards
Delicious77 [7]
There were...
11cards left.
heres why.
they started with 24 cards....
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Hope i helped!!! :)
Mark me as brainliest if i helped XD
6 0
3 years ago
The transformation of the function f(x) = 2x when it becomes f(x) = 2x-4 is a horizontal shift of 4 units to the left.
Natasha_Volkova [10]
No it is actually a horizontal shift of 2 units to the right. 
6 0
3 years ago
A rectangular mat has a length of 12 in. and a width of 4 in. Drawn on the mat are three circles. Each circle has a radius of 2
AVprozaik [17]
Area of the rectangular mat = 12 x 4 = 48 in²

Area of the 3 circles = 3( πr²) = 3(3.14 x 2²) = 37.68 in²

P(landing in a circle) = 37.68/48 = 157/200 = 0.79 (nearest hundredth)

Answer: The probability of landing in one of the circles is 0.79.
7 0
3 years ago
Someone plz help with this question. I really appreciate it!
kirill115 [55]

8. D: The <em>longest sides of the quadrilaterals are 30 and 10</em>. That is a 30 : 10 ratio, which simplifies to <em>3 : 1, or </em>3/1. It's not 1 : 3 because it is the ratio between the large (comes first) to the small (comes second) figure.

9. B: <em>x corresponds to 26</em>, and from the previous problem, we figured out that <em>the sides of the larger figure are 3 times larger than the corresponding one on the smaller one</em>. So <em>x is 1/3 the length of 26</em>, which is 26/3.

8 0
3 years ago
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