Answer:
Infinitely many solutions.
Step-by-step explanation:
Let's begin by carrying out the indicated multiplications, which must be done before any addition or subtraction:
2(8r+5)-3=4(4r-1)+11 becomes 16r + 10 - 3 = 16r - 4 + 11.
Subtracting 16r from both sides, we get 10 - 3 = - 4 + 11, or 7 = 7
This is always true, so we can conclude that this equation has infinitely many solutions.
I hope it helped youuuuuu
1=5-4 because you have to substitute x and y (x,y) or (5,1)
<span>-8 < x -3 < 1
we have two inequations:
* -8<x-3 and -8+3<x-3+3 or -5 < x or x>-5
* x-3<1 or x-3+3<1+3 and we have x<4
For all cases we have -5<x<4
or </span><span>interval notations: x</span>∈(-5;4)
have fun
