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rusak2 [61]
2 years ago
9

Solve the quadratic equation 2x + x-7 = 0 Give your answers to 2 decimal places.

Mathematics
1 answer:
Yakvenalex [24]2 years ago
3 0

\text{Its not a quadratic equation but the answer is 2.33}

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Suppose f is a continuous function on [-2, 2) such that
Leviafan [203]

Answer:

2. a and b only.

Step-by-step explanation:

We can check all of the given conditions to see which is true and which false.

a. f(c)=0 for some c in (-2,2).

According to the intermediate value theorem this must be true, since the extreme values of the function are f(-2)=1 and f(2)=-1, so according to the theorem, there must be one x-value for which f(x)=0 (middle value between the extreme values) if the function is continuous.

b. the graph of f(-x)+x crosses the x-axis on (-2,2)

Let's test this condition, we will substitute x for the given values on the interval so we get:

f(-(-2))+(-2)

f(2)-2

-1-1=-3  lower limit

f(-2)+2

1+2=3 higher limit

according to these results, the graph must cross the x-axis at some point so the graph can move from f(x)=-3 to f(x)=3, so this must be true.

c. f(c)<1 for all c in (-2,2)

even though this might be true for some x-values of of the interval, there are some other points where this might not be the case. You can find one of those situations when finding f(-2)=1, which is a positive value of f(c), so this must be false.

The final answer is then 2. a and b only.

4 0
3 years ago
Simplify the complex fraction.<br> Simplify.<br> 5<br> 9<br> 4<br> 15
Sedaia [141]

Answer:

im confused?

Step-by-step explanation:

could you please rewrite this question? what are the numbers for?

5 0
2 years ago
What is the formula that relates circumference and radius?
bixtya [17]
All the options are incorrect, if you're talking about circle! which is most common
C = 2πr..... It is the relation for Circle's if you're considering something else, then, please mention!
6 0
3 years ago
Read 2 more answers
10 POINTS only answer if you KNOW
kenny6666 [7]
The answer is D, tony would always be behind Robert.
5 0
3 years ago
Use the binomial expansion and approximation to find √3​
belka [17]

According to the use of binomial expansion, the approximate value of √3 is found by applying the infinite sum √3 = 1 + (1 /2) · 2 - (1 / 8) · 2² + (1 / 16) · 2³ - (5 / 128) · 2⁴ + (7 / 256) · 2⁵ - (21 / 1024) · 2⁶ + (33 / 2048) · 2⁷ - (429 / 32768) · 2⁸ +...

An acceptable result cannot be found manually for it requires a <em>high</em> number of elements, with the help of a solver we find that the <em>approximate</em> value of √3 is 1.732.  

<h3>How to approximate the value of a irrational number by binomial theorem</h3>

Binomial theorem offers a formula to find the <em>analytical</em> form of the power of a binomial of the form (a + b)ⁿ:

(a + b)^{n} = \sum \limits_{k = 0}^{n} \left(\begin{array}{c}n\\k\end{array}\right)\cdot a^{n-k} \cdot b^{k}     (1)

Where:

  • a, b - Constants of the binomial.
  • n - Grade of the power binomial.
  • k - Index of the k-th element of the power binomial.

If we know that a = 1, b = 2 and n = 1 / 2, then an approximate expression for the square root is:

√3 = 1 + (1 /2) · 2 - (1 / 8) · 2² + (1 / 16) · 2³ - (5 / 128) · 2⁴ + (7 / 256) · 2⁵ - (21 / 1024) · 2⁶ + (33 / 2048) · 2⁷ - (429 / 32768) · 2⁸ +...

To learn more on binomial expansions: brainly.com/question/12249986

#SPJ1

8 0
1 year ago
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