Whenever a problem says "one number" and "another number" we can substitute x and y. for this we have x=2y+1 and xy=1. since we know the value of x (2y+1) we can substitute it for the other equation to get (2y+1)y=10. simplify to get 2y^2+y=10. from here you can do a few methods to solve this, but the simplest in my opinion is by factoring.
In order to factor it must be equal to 0, so we have 2y^2+y-10=0. We factor this and get y=5 (we also get y=-4 but it is an extraneous root). now we can plug that into either equation and find that x=2.
this means our two numbers are 5 and 2
A^2 + b^2= c^2
(a,b,c are right triangle sides)
Answer:
do you need all work shown for this problem
A. 6xy(2x^2y^2-4xy^2)
If you need to multiply 6xy and 2x^2y^2 & 6xy and 4xy^2.
You will get 12x^3y^3-24x^2y^3.
b. Factorization is not complete because 6xy is not the greatest common factor.
c. Complete factor: 12x^2y^3(x-2y).
Answer:
214°
Step-by-step explanation:
Full circle measure = 360°
Measure of arc AB = 146° (central angle has the same measure as measure of intercepted arc)
Therefore:
Measure of arc ACB = 360° - arc AB
Measure of arc ACB = 360° - 146°
= 214°
