We have trapezoid with congruent legs.
30x + 11y = 2x + 3
28x +11y = 3
Also we have
30x + 11y = 12
We got 2 equations:
30x + 11y = 12
28x +11y = 3 (*-1) -----> -28x -11y = -3
30x + 11y = 12
<u> -28x -11y = -3</u>
2x = 9
x=9/2
30x + 11y = 12 ------> 30*9/2 +11y =12 ------> 135+11y =12, ---> 11y = - 123,
y= - 123/11
Answer:
0.002
Step-by-step explanation:
Answer:
the bus took 4.5 hrs going 60 kph to get from town P to town Q
this means that the distance from town P to town Q is 270 km
side note-the car kph isn't shown and it got to town Q faster than the bus, so it must have gone at a faster speed. i didn't use the car to solve the problem, just the bus.
Answer:
Start at postive 1 on the y axis put a dot there. From the dot go down 6 and go left 5.
Step-by-step explanation:
6/5=rise over run
1=y-axis
y=mx+b
m=slope
b=y-intersept
Parent function: y =x3 ; shift
4 units to the left
