Answer:
maybe the arrows should start from zero, probably
I had this before and I think is was A.
Let
be the 20 marks of the boys, and
be the 10 marks of the girls.
We know that the global mean was 70, meaning that
![\dfrac{b_1+b_2+\ldots+b_{20}+g_1+g_2+\ldots+g_{10}}{30}=70](https://tex.z-dn.net/?f=%5Cdfrac%7Bb_1%2Bb_2%2B%5Cldots%2Bb_%7B20%7D%2Bg_1%2Bg_2%2B%5Cldots%2Bg_%7B10%7D%7D%7B30%7D%3D70)
Multiplying both sides by 30 we deduce that the sum of the scores of the whole classroom is
![b_1+b_2+\ldots+b_{20}+g_1+g_2+\ldots+g_{10}=2100](https://tex.z-dn.net/?f=b_1%2Bb_2%2B%5Cldots%2Bb_%7B20%7D%2Bg_1%2Bg_2%2B%5Cldots%2Bg_%7B10%7D%3D2100)
By the same logic, we work with the marks of the boys alone: we know the average:
![\dfrac{b_1+b_2+\ldots+b_{20}}{20}=62](https://tex.z-dn.net/?f=%5Cdfrac%7Bb_1%2Bb_2%2B%5Cldots%2Bb_%7B20%7D%7D%7B20%7D%3D62)
And we deduce the sum of the marks for the boys:
![b_1+b_2+\ldots+b_{20}=1240](https://tex.z-dn.net/?f=b_1%2Bb_2%2B%5Cldots%2Bb_%7B20%7D%3D1240)
Which implies that the sum of the marks of the girls is ![2100-1240=860](https://tex.z-dn.net/?f=2100-1240%3D860)
And finally, the mean for the girls alone is
![\dfrac{860}{10}=86](https://tex.z-dn.net/?f=%5Cdfrac%7B860%7D%7B10%7D%3D86)
Line perpendicular to a given line is = 1/m
To find m, use m =y2-y1/x2-x1 formula
m = (8-(-3))/(-7-4)
m = 11/-11,
m = -1
Use y= mx+c to find equation of line
Plug in a pair of values,
-3= -1(4)+ c
c= 1
Thus, equation is:
y = -x+1
Equation of line perpendicular to this line is:
y= x+1
Hope it helps :)
Pls mark it as Brainliest :)
Answer:
$5.61
Step-by-step explanation:
Since David only has $9.39 but he needs $15.00 for his purchase. So, you would subtract the $9.39 from the $15.00 to see how much more money David needs to make this purchase.
15.00 - 9.39
When you carry out this problem, it equals $5.61.
Therefore, David needs $5.61 to be able to complete his purchase