Given the sequence 5, 6, 7, 8, ....., where x = 1, 2, 3, 4, ...., what is the first term in the sequence?
wel
The first term in the sequence is 5.
<u>Step-by-step explanation</u>:
The sequence is 5,6,7,8,.....
- The first term = 5
- The second term = 6
- The third term = 7
where x= 1,2,3,4,...
The sequence follows the pattern (x+4).
- For x=1, then (1+4) = 5 which is the first term of the sequence.
Similarly,
- For x=2, then (2+4) = 6 which is the second term of the sequence and the sequence follows the same pattern.
Answer:
c
Step-by-step explanation:
Answer: -9
(-3) ³= -27
6 ³/12 = 216/12 = 18
-27+18=-9
Easy just use the method rise over run
<u>Answer:</u>
1 ,
(Answer)
<u>Step-by-step explanation:</u>
Since, 8 chips are selected at random and 5 are there defectives in the lot, So, at least (8 - 5) = 3 chosen chips will be non - defective.
So, P ( At least two of selected part is non defective ) = 1 .
P(first and second samples are defective)
= 
P ( first, second and third samples are defective)
= 
So,

=
= 
=
(Answer)