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Shkiper50 [21]
2 years ago
6

Based on a​ poll, 63% of Internet users are more careful about personal information when using a public​ Wi-Fi hotspot. What is

the probability that among four randomly selected Internet​ users, at least one is more careful about personal information when using a public​ Wi-Fi hotspot? How is the result affected by the additional information that the survey subjects volunteered to​ respond? The probability that at least one of them is careful about personal information is
Mathematics
1 answer:
VashaNatasha [74]2 years ago
3 0

Answer:

So it's a big probability it's a 6 in 4 chance though. 6 is for users that are careful and 4 for users that aren't that careful.

Step-by-step explanation:

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The first term in the sequence is 5.

<u>Step-by-step explanation</u>:

The sequence is 5,6,7,8,.....

  • The first term = 5
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where x= 1,2,3,4,...

The sequence follows the pattern (x+4).

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Similarly,

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A lot of 200 chips contain 5 that are defective. 8 are selected random with out replacement.
vaieri [72.5K]

<u>Answer:</u>

1 , \frac{1}{66}  (Answer)

<u>Step-by-step explanation:</u>

Since, 8 chips are selected at random and 5 are there defectives in the lot, So, at least (8 - 5) = 3 chosen chips will be non - defective.

So, P ( At least two of selected part is non defective ) = 1 .

P(first and second samples are defective)

= \frac{5 \times 4}{200 \times 199}

P ( first, second and third samples are defective)

= \frac{5 \times 4 \times 3}{200 \times 199 \times 198}

So,

\frac{{\textrm{Third sample is defective | first and second samples are defectives}}}

=\frac{{\textrm{  P ( first, second and third samples are defective)}}}{{\textrm{  P(first and second samples are defective) }}}

= \frac{3}{198}

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