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Shkiper50 [21]
2 years ago
6

Based on a​ poll, 63% of Internet users are more careful about personal information when using a public​ Wi-Fi hotspot. What is

the probability that among four randomly selected Internet​ users, at least one is more careful about personal information when using a public​ Wi-Fi hotspot? How is the result affected by the additional information that the survey subjects volunteered to​ respond? The probability that at least one of them is careful about personal information is
Mathematics
1 answer:
VashaNatasha [74]2 years ago
3 0

Answer:

So it's a big probability it's a 6 in 4 chance though. 6 is for users that are careful and 4 for users that aren't that careful.

Step-by-step explanation:

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a delivery truck is transporting boxes of two sizes: large and small. The combined weight of a large box and a small box is 90 p
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45

Step-by-step explanation:

70 + 65 = 135 boxed both large and small.

6150 / 135 = 45 pounds estimated.

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Using your own words, create a word problem around the given problem. Then solve it
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Philip got $300 from his relatives, he puts 65% of the money he got into the bank. How much money did Philip put in the bank? $195

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Suppose that y varies directly with x and inversely with z, and y = 8 when x = 4 and z =
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Given that (x+y+z)(xy+xz+yz)=18 and that x^2(y+z)+y^2(x+z)+z^2(x+y)=6 for real numbers x, y, and z, what is the value of xyz?
worty [1.4K]

Answer:

4

Step-by-step explanation:

(x+y+z)(xy+xz+yz)=18 Equation 1

x^2(y+z)+y^2(x+z)+z^2(x+y)=6 Equation 2

What is the value of xyz where each variable represents a real number?

Let's expand equation 1:

(x+y+z)(xy+xz+yz)=18

x(xy)+x(xz)+x(yz)+y(xy)+y(xz)+y(yz)+z(xy)+z(xz)+z(yz)=18

Simplify each term if can:

x^2y+x^2z+xyz+y^2x+xyz+y^2z+xyz+z^2x+z^2y=18

See if we can factor a little to get some of the left hand side of equation 2:

The first two terms have x^2 and if I factored x^2 from first two terms I would have x^2(y+z) which is the first term of left hand side of equation 2.

So let's see what happens if we gather the terms together that have the same variable squared together.

x^2y+x^2z+y^2x+y^2z+z^2y+z^2x+xyz+xyz+xyz=18

Factor the variable squared terms out of each binomial pairing:

x^2(y+z)+y^2(x+z)+z^2(y+x)+xyz+xyz+xyz=18

Replace the sum of those first three terms with what it equals which is 6 from the equation 2:

6+xyz+xyz+xyz=18

Combine like terms:

6+3xyz=18

Subtract 6 on both sides:

3xyz=12

Divide both sides by 3:

xyz=4

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3 years ago
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Answer:

(a) is False (b) is true (c) is true

Step-by-step explanation:

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