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Alja [10]
3 years ago
8

PLEASE HELP PERSONAL FINANCE / LAUNCH QUESTION

Mathematics
1 answer:
Kobotan [32]3 years ago
3 0

Answer:

option d: 25% unfavorable

Step-by-step explanation:

The budget is $40, and it was spent $50, so as the amount spent was higher than the budget, we have a unfavorable percent of variance.

The amount spent more than the budget was:

50 - 40 = 10

Now to calculate the percent of variance, we divide the value spent more than the budget (10) by the value of the budget (40)

Percent of variance = 10 / 40 = 0.25 = 25%

So the answer is 25% unfavorable, option d

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The mean of a set of eight numbers is 8 and the mean of a different set of twelve numbers is m. Given that the mean if the combi
Basile [38]
Mean=total/the number of values =>total=mean*the number of values
the total of the first set of 8 numbers is : total=8*8=64
the total of the second set of 12 numbers is: 12m
the total of the 20 numbers is: 64+12m
the mean of the 20 number is: (64+12m)/20=5
solve for m: 64+12m=100
12m=36
m=3
8 0
3 years ago
Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5
givi [52]
<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]                            X=\left[\begin{array}{c}x\\y\end{array}\right]

and          B= \left[\begin{array}{c}11\\5\end{array}\right]

∴AX=B

adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]

A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6

∴A^{-1} =\frac{adj A}{|A|}

So,A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}

A^{-1} ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}

X =A^{-1}\times B

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c}  {6}\\  {11} \end{array}\right]}

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0
2 years ago
Which of the following statements about feasible solutions to a linear programming problem is true?A. Min 4x + 3y + (2/3)z
Len [333]

Answer:

The answer is "Option A"

Step-by-step explanation:

The valid linear programming language equation can be defined as follows:

Equation:

\Rightarrow \ Min\  4x + 3y + (\frac{2}{3})z

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Formula:

\to \boxed{y= mx+c}

7 0
3 years ago
The first table that Cory designs will seat 8 people. If the diameter is 5 feet, what is the area? The area in terms of pi is Pi
frutty [35]

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Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Part À : Find a rational number that is between 9.5 and 9.7 - Explain why is it rational
noname [10]

9514 1404 393

Answer:

  A.  9.6

  B. √92 ≈ 9.59

Step-by-step explanation:

A. 9.6 is a rational number between 9.5 and 9.7. It is rational because it is a terminating decimal.

__

B. √92 is an irrational number between 9.5 and 9.7. It is irrational because it is the square root of an integer that is not a perfect square. Its decimal value is about 9.59.

6 0
3 years ago
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