Question

The areas of the squares adjacent to two sides of a right triangle are 32units^2 and 32 units^2

Answer 1

Answer:

Step-by-step explanationmoo

Answer 2

Answer:

x = 8 units.

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  

The areas of the squares adjacent to two sides of a right triangle are 32 unit square and 32 units square. Find the length,x, of the third side of the triangle

My answer:

• Let a is the side length of the 1st square

The area of the 1st square is equal to 32 units square

<=> $a^{2} = 32$

<=> a = $4\sqrt{2}$ units

• Let b is the length  of the 2nd  square

The area of the 2nd square is equal to 32 units square

<=> $b^{2}$ = 32

<=> b = $4\sqrt{2}$ units

• Find the value of x

Applying the Pythagoras Theorem, we have:

$x^{2} = a^{2} + b^{2}$

<=> $x^{2} = 32 + 32$  

<=> $x^{2} = 64$

<=> x = 8 units

Hope it will find you well.